The value of X is 10 hence the formula of unknown hydrate sodium sulfate is NaSO4.10 H20
calculation
step 1:find the moles of NaSO4 and the moles of H2O
moles= mass/molar mass
moles of Na2SO4=1.42÷142=0.01 moles
moles of H20= mass of H2O/molar mass of H2O
mass of H2O= 3.22-1.42=1.8g
mole of H2O is therefore 1.8÷18=0.1 moles
step 2: find the mole ratio by dividing each mole by smallest number of mole (0.01)
that is Na2So4= 0.01/0.01 =1
H2O= 0.1/0.01=10
Volume of the nitrogen gas = 49.8 L
<u>Explanation:</u>
It is given that the pressure, number of moles and temperature of nitrogen gas, and gas constant value being constant and it is taken as 0.08206 L atm mol⁻¹K⁻¹.
Temperature = T = 75°C = 75 + 273 = 348 K
Pressure = P = 0.992 atm
Number of moles = n = 1.73 moles
We have to use the ideal gas equation, PV = nRT, and rearranging the equation to get Volume in litres.
V = 
= 
= 49.8 L
So the volume of Nitrogen gas = 49.8 L
Answer:
HOMO of 1,3-butadiene and LUMO of ethylene
HOMO of ethylene LUMO of 1,3-butadiene
Explanation:
1,3 - butadiene underogoes cycloaddition reaction with ethylene to give cyclohexene.
According to Frontier molecular orbital theory HOMO of 1,3 butadiene and LUMO of ethylene and HOMO of ethylene and LUMO of ethylene underoges (4 + 2) in thermal or photochemical condition.
First convert grams to moles:
70.0g *(mole/98.079) = 0.7137mole
Remember that molarity is moles per liter:
0.7137mole *(1/280mL) *(1000mL/L) = 25.5M