Petra jogs 3 miles in 30 minutes. At this rate, how long would it take her to jog 7 miles?
1 answer:
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Answer:
1. f₁(x)=-x²+2x-2
2. f₂(x)=-x²+6x-10
3. f₃(x)=-x²-2
4. f₄(x)=-x²+10x-26
5. f₅(x)=-x²-2x-2
6. f₆(x)=-x²
Step-by-step explanation:
1. we have that f(x) is translated right by 1 unit , also
according to the graph f(x) has a vertex P(0,-1) then P₁ ( 1,-1) to f₁(x) therefore y-y₁ = -(x-x₁)² ⇒ y-y₁ = -(x-x₁)² ⇒ y+1 = -(x-1)² ⇒ y=-(x²-2x+1)-1 =-x²+2x-2
2. f(x) is reflected across the x-axis 3, same as in 1., P₂(3,-1) to f₂(x)
y+1 = -(x-3)² ⇒ y=-(x²-6x+9)-1 =-x²+6x-10
3. f(x) is translated down by 1 unit, P₃(0,-2) to f₃(x)
y+2 = -(x)² ⇒ y=-x²-2
4. f(x) is reflected across the y-axis 5, P₄(5,-1) to f₄(x)
y+1 = -(x-5)² ⇒ y=-(x²-10x+25)-1 =-x²+10x-26
5. f(x) is translated left by 1, P₅(-1,-1) to f₅(x)
y+1 = -(x+1)² ⇒ y=-(x²+2x+1)-1 =-x²-2x-2
6. f(x) is translated up by 1 unit, P₆(0,0) to f₆(x)
y+0 = -(x+0)² ⇒ y=-x²
Answer:
mass of the water removed = 66.67 kg
Step-by-step explanation:
given data
solids is blended with sugar = 10%
obtain final product = 15% product
obtain final product = 15% sugar solids
The initial product is = 200 kg
solution
we get here amount of sugar required that is
amount of sugar required = 200 ×
amount of sugar required = 20 kg
and we know total solid = product solids + sugar solids ...............1
and
initial product = final product
so
0.20 × 200kg= 0.30 × mass of the final product
mass of final product = 133.33 kg
but here
final product = 15% product solids and 15% sugar solids
so that amount of product solid = sugar solid
so
mass of the water removed = 200 kg - 133.33 kg
mass of the water removed = 66.67 kg