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Vlada [557]
2 years ago
11

Determine, if possible, if (x – 8) is a factor of (x3 – 3x2 – 31x – 72). A. Only if x = 2 B. Yes C. No D. Not enough information

to determine
Mathematics
2 answers:
vovikov84 [41]2 years ago
8 0
The polynomial remainder theorem says when we divide polynomial f(x) by x-a we'll get remainder f(a).

f(x)=x^3 - 3x^2 - 31x - 72

f(8)=8^3 - 3(8^2) - 31(8) - 72

f(8)=512 - 3(64) - 31(8) - 72 = 512-192-248-72 = 0

Since <em>f(8)=0</em> that means <em>x-8</em> has a remainder zero when divided by <em>f(x).</em> In other words, it's a factor of <em>f(x)</em>.

Answer B
 
Annette [7]2 years ago
3 0
I believe the answer is C
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Judy’s measured potassium level varies according to the Normal distribution with μ = 3.8 and σ = 0.2 mmol/l. Let us consider wha
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Answer:

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 3.8, \sigma = 0.2, n = 4, s = \frac{0.2}{\sqrt{4}} = 0.1

What is the blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L?

This is the value of X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 3.8}{0.1}

X - 3.8 = -1.645*0.1

X = 3.64

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

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