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Molodets [167]
2 years ago
3

Using an electron microscope, Jane measured a rod-shaped bacterium and found it to be 0.00000345 meters in length. List the step

s she should take to represent this number in scientific notation.
Physics
2 answers:
lubasha [3.4K]2 years ago
5 0

1. Identify the position of the decimal point in the number

2. Determine where to move the decimal to the first non-zero number from the left (which is less than 10 definitely)

3. Write down the non-zero number (denoted by C) and then count the decimal places moves from the original decimal position to the final decimal position.

4. The number of decimal places moved (denoted by n) will be the exponent of base 10

5. Therefore the scientific notation will look like : C * 10^n

6. Note that n can be negative or positive (In this case, it is negative because the decimal is moved towards the right)


Following these steps, scientific notation in our case becomes 3.45 * 10^6

lidiya [134]2 years ago
4 0

Answer:

1. Identify the position of the decimal point in the number

2. Determine where to move the decimal to the first non-zero number from the left (which is less than 10 definitely)

3. Write down the non-zero number (denoted by C) and then count the decimal places moves from the original decimal position to the final decimal position.

4. The number of decimal places moved (denoted by n) will be the exponent of base 10

5. Therefore the scientific notation will look like : C * 10^n

6. Note that n can be negative or positive (In this case, it is negative because the decimal is moved towards the right)

Explanation:

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The problem states that the distance travelled (d) is directly proportional to the square of time (t^2), therefore we can write this in the form of:

d = k t^2

where k is the constant of proportionality in furlongs / s^2

 

<span>Using the 1st condition where d = 2 furlongs, t = 2 s, we calculate for the value of k:</span>

2 = k (2)^2

k = 2 / 4

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The equation becomes:

d = 0.5 t^2

 

Now solving for d when t = 4:

d = 0.5 (4)^2

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8 0
2 years ago
Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p
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We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

  • U1/U2=6
  • U1/U2=6

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy  is mathematically given as

U=\frac{-k*qQ}{r}

Therefore

The Equations of U1 and U2 is

For U1

U1=\frac{-k*q_1Q}{r}

For U2

U2=\frac{-k*q_1Q}{3*2r}

Since

U is a function of q and  q2=q1/3

Therefore

U1/U2=6

For Question 2

For U1

U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}

Therefore

U1/U2=6

For more information on this visit

brainly.com/question/23379286?referrer=searchResults

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Check the attached file for the answer.

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