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lesya [120]
2 years ago
6

Which of the following equations correctly represents a circle centered at the origin with a radius of 7?A. (x - 7)2 + y2 = 49 B

. x2 + y2 = 72 C. x2 + y2 = 7 D. (x - 7)2 + (y - 7)2 = 72
Mathematics
2 answers:
Damm [24]2 years ago
7 0

Answer:

Option B. (x)^{2}+(y)^{2} =7^{2}

Step-by-step explanation:

we know that

The equation of a circle into center radius form is equal to

(x-h)^{2}+(y-k)^{2} =r^{2}

where

(h,k) is the center

r is the radius

In this problem we have

(h,k)=(0,0) -----> because the center is at the origin

r=7\ units

substitute

(x-0)^{2}+(y-0)^{2} =7^{2}

(x)^{2}+(y)^{2} =7^{2}

Gala2k [10]2 years ago
4 0

"a circle centered at the origin with a radius of 7" has the form x^2 + y^2 = r^2. Here, r = 7, so the desired equation is x^2 + y^2 = 7^2.

None of the given answers is correct.

Ensure that you've copied the problem accurately.

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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
2 years ago
Read 2 more answers
The population of a small town is decreasing exponentially at a rate of 14.3% each year. The current population is 9,400 people.
levacccp [35]

Answer:

After 2.9 years the town's tax status will change

The towns tax status change within the next 3 years

Step-by-step explanation:

The question below is

Will the towns tax status change within the next 3 years ?

Let

y -----> the population of a small town

t ----> the number of years

we have a exponential function of the form

y=a(b)^{t}

where

a is the initial value

b is the base

In this problem

a=9,400\ people

b=100\%-14.3\%=85.7\%=85.7/100=0.857

substitute

y=9,400(0.857)^{t}

Remember that

The town's tax status will change once the population is below 6,000 people

so

The inequality that represent this situation is

9,400(0.857)^{t}< 6,000    

Solve for t

(0.857)^{t}< 6,000/9,400

Apply log both sides

(t)log(0.857)< log(6,000/9,400)

-0.067t< -0.1950

Multiply by -1 both sides

0.067t > 0.1950

t > 2.9\ years

so

After 2.9 years the town's tax status will change

therefore

The answer is

Yes, the towns tax status change within the next 3 years

6 0
2 years ago
On a Friday evening a pizza shop had orders for 4 pepperoni, 97, and 335 cheese pizzas. If the 4 cooks each made an equal number
aksik [14]
Add the order of pizzas together and divide by four.  Round your answer.
5 0
2 years ago
Read 2 more answers
As part of Kayla's exercise program,she either runs 6miles/day or rides her bike 10 miles/day.Her new goal is to cover a minimum
poizon [28]
6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11

so she can do 15 days of running plus 11 days of biking....which totals 26 days

8 0
2 years ago
Suppose that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 poi
AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of university​ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A)P(X>135) = \\P(Z>0.625)\\=0.0266

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and Var (x-y)=Var(x)+Var(y) = 19

P(X-Y)>5\\\\=1-0.00029\\=0.9997

C) For a group of 3, average has std deviation = \frac{11}{\sqrt{3} } \\=6.351

P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856

3 0
2 years ago
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