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Arturiano [62]
2 years ago
11

The city council is planning a long, narrow park with a playground at one end and a fountain at the other. They want the playgro

und more than 5 blocks from the fountain and both items at least 2 blocks from the center of the park. The graph below represents the possible positions of the playground, relative to the center of the park. Which compound inequality represents the possible positions of the playground?
Numberline with filled circle at -2 and shading to left with an open circle at 3 and shading to the right

Group of answer choices

2x ≥ −2 and x < −3

x + 3 ≤ 1 and −x > −3

x + 4 ≤ 2 or x + 4 > 7

2x − 1 ≥ −5 or 3x < 9
Mathematics
1 answer:
FrozenT [24]2 years ago
6 0

Answer:

b

Step-by-step explanation:

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A 10K run is 10 kilometers long. If 1 meter = 1.094 yards, use dimensional analysis to find the length of the race in miles. (Hi
laila [671]
10936.1 yards = 10 kilometers                                                                              1 kilometer = 1093.1 yards                  



7 0
2 years ago
Read 2 more answers
Suppose that for a recent admissions class, an Ivy League college received 2,851 applications for early admission. Of this group
stepan [7]

Answer:

A) The probability is a measure of the likelihood than an event is going to occur. In this case we can calculate the probability of X as:

P(X) = X/N where X is the number of ways X occurs and N is the total number of events.

P(E) = E/N = 1033/2851 = 0.3623

P(R) = R/N = 854/2851 = 0.2995

P(D) = D/N = 964/2851 = 0.3381

B)

E and D are mutually exclusive because the students that were admitted early where not deffered to regular admission pool. There is no chance that there is a student that were admitted erarly and deffered at the same time, so the intersection between E and D (E∩D) is 0.

C) The number of students that were early accepted is 1033 and the total number of students accepted is 2375. The probability is going to be:

P = 1033/2375 = 0.4349

D)

In this case we can reformulate the question as: What is the probability of being accepted if you apply for early admission? This

Since 18% of the students deffered to regular admission pool 0.18 × 964 = 174 were admitted at the end.

The probability of being deffered and then accepted is going to be:

P(DA) = 174/2831 = 0.0610

The probability of ramdomly selecting a students that has been early accepted or deffered and then accepted is going to be:

P(E or DA) = 0.0610 + 0.3623 = 0.4233

This is the addition rule.

3 0
2 years ago
Find the sum of the first 63 terms of –19, -13, -7 …
boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

Given n = 63 and we found a = -19 and d = 6

\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)

\implies S_6_3 = \frac{63}{2}(-38 + (62)6)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(-38 + 372)

\implies S_6_3 = \frac{63}{2}(334)

\implies S_6_3 = {63}(167) = 10521

The Sum of First 63 terms is 10521

4 0
2 years ago
A grocery store gives away a $10 gift card to every 25th customer and a $20 gift card to every 60th customer. Which customer wil
Novosadov [1.4K]
The 300th customer would be the first to recieve both. They would have given away 5 of the 20$ gift cards and 12 of the 10$ ones for a total of 17 gift cards.
7 0
2 years ago
In a school of 2100 students, the ratio of teachers to students is 1:14. Some teachers join the school and the ratio changes to
mrs_skeptik [129]

Answer:

50 Teachers

Step-by-step explanation:

To solve this problem, we first need to find the number of teachers <em>before </em>the new teachers were added. To do so, I created Model 1. On the bottom of the ratios, we have students. On the top, is teachers. The X is the number of teachers we are trying to find. Following the model, I multiplied 2,100 x 1 (2,100) and divided it by 14 to get 150 teachers. Then, I set up a similar model with the new student-teacher ratio (Model 2). From there, I multiplied 2,100 x 2 (4,200) and divided it by 21 to get 200 teachers. Now I have the original number of teachers and the new number of teachers. Subtract the new by the original to find the teachers added and you get the answer of 50 teachers added.

6 0
2 years ago
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