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Masteriza [31]
2 years ago
7

explains why heating a liquid affects its viscosity? The molecules move faster at higher temperatures and overcome attractions m

ore easily. The molecules move faster at higher temperatures, and the attractions between them increase. The molecules move slower at higher temperatures and overcome attractions more easily. The molecules move slower at higher temperatures, and the attractions between them decrease.
Chemistry
2 answers:
zmey [24]2 years ago
6 0

<span>I think the correct answer is option 1. Heating a liquid affects the viscosity of the liquid because </span><span>molecules move faster at higher temperatures and overcome attractions more easily. Overcoming the attractions in the substance would decrease the viscosity of the liquid.</span>

Aleksandr-060686 [28]2 years ago
3 0

Answer:

i think it is a

Explanation:

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A student has two samples of NaCl, each one from a different source. Assume that the only potential contaminant in each sample i
bija089 [108]

Answer:

The correct option is;

A. Which sample has the higher purity

Explanation:

The information given relate to the presence of two samples of NaCl, from different sources

The only potential contaminant in each of the sources = KCl

The content of the sample = NaCl

The molar mass of NaCl = 58.44 g/mol

The molar mass of KCl = 74.5513 g/mol

Let the number of moles of KCl in the sample = X

For a given mass of NaCl, KCl mixture, we have;

The molar mass of potassium = 39.0983 g/mol

The molar mass of chlorine = 35.453 g/mol

The molar mass of sodium ≈ 23 g/mol

Therefore;

Each mole of KCl, will yield 35.453 g/mol per 74.5513 g/mol of KCl

While each mole of NaCl will yield 35.453 g/mol per 58.44 g/mol of NaCl

Therefore, the pure sodium chloride sample will yield more chlorine per unit mass of sample.

As such if the two samples have the same mass, the sample with the contaminant of KCl will yield less mass of chlorine per unit mass of the sample, from which the student will be able to tell the purity of the solution.

The sample with the higher purity will yield  a higher mass chlorine per unit mass of the sample.

6 0
2 years ago
Describe how you could determine the specific heat of a sample of a solid substance. You may assume that the substance does not
lesya692 [45]
<span>I would measure the mass of the solid substance. I would prepare a known mass of room temperature water large enough to submerge the solid substance in question. I would place the water in an insulated container. Then I would heat the solid substance to a known temperature. I would measure the temperature of the heated sample and the water. Then I would submerge the sample in the water and allow the sample and the water to reach the same temperature. I would measure this equilibrium temperature. I would interpret the difference in temperature between the heated sample and the equilibrium temperature as the change in temperature in the sample. Given the known mass, the beginning temperature of the water, and the equilibrium temperature I can determine how much energy was transferred from the heated sample to the water. Now the mass of the sample, a change in temperature in the solid substance, and the amount of energy transferred to create the temperature is known. This is sufficient to determine the specific heat of the solid substance</span>
6 0
2 years ago
Read 2 more answers
What is the maximum number of grams of ammonia, nh3, which can be obtained from the reaction of 10.0 g of h2 and 80.0 g of n2? n
Lelechka [254]

<u>Answer:</u> The mass of ammonia produced is 28.22 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 10.0 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5mol

  • <u>For nitrogen gas:</u>

Given mass of nitrogen gas = 80.0 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

\text{Moles of nitrogen gas}=\frac{80.0g}{28g/mol}=2.86mol

The given chemical equation follows:

N_2+3H_2\rightarrow 2NH_3

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas

So, 5 moles of hydrogen gas will react with = \frac{1}{3}\times 5=1.66mol of nitrogen gas

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 1 mole of ammonia

So, 5 moles of hydrogen gas will produce = \frac{1}{3}\times 5=1.66moles of ammonia

Now, calculating the mass of ammonia from equation 1, we get:

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 1.66 moles

Putting values in equation 1, we get:

1.66mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(1.66mol\times 17g/mol)=28.22g

Hence, the mass of ammonia produced is 28.22 g

4 0
2 years ago
How much maleic anhydride would you need to react 178 mg of anthracene? Assume 1:1 ratio from maleic anhydride to anthracene.
Licemer1 [7]

Answer:

(1) 0.10      (2) 17.8 g

Explanation:

Since the reaction ratio is 1:1 what we need is to convert the given masses to moles and you will have the answer:

MW anthracene = 178.23 g/mol

MW maleic anhydride = 98.06 g/mol

a) mass anthracene = 178 mg x 1 g/ 1000 mg = 0.178 g anthracene

Moles anthracene = 0.178 g anthracene/ 178.23 g/mol

= 0.001 mol anthracene

0.001 mol anthracene x 1 mol maleic acid/mol anthracene

= 0.001 mol maleic anhydride

mass maleic anhydride  = 0.001 mol x 98.06 g/mol =  0.10 g

b) moles maleic anhydride = 9.8 g/ 98.06 g/mol = 0.099 moles

0.099 moles maleic anhydride x 1 mol anthracene/mol  maleic anhydride =

0.099 mol anthracene

g anthracene = 0.10mol x 178 g/mol = 17.8 g

8 0
2 years ago
Hydrazine (N2H4) and dinitrogen tetroxide (N2O4) form a self-igniting mixture that has been used as a rocket propellant. The rea
Alexxx [7]

Answer:

Explanation:

An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.

Chemical equation:

1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O

2) Hydrazine ( N₂H₄)  is being oxidized

Dinitrogen tetroxide N₂O₄ is being reduced

3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)

5 0
2 years ago
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