Question

A certain class of 160 students has 40 honor students and 60 athletes. Eighty students in the class do not participate in sports and are not honor students. If a student is selected at random to represent the class, what is the probability that he is both an honor student and an athlete?

Answer 1

62.5%

My Proof:

100:160*100 =

(100*100):160 =

10000:160 = 62.5

Answer 2

Answer:

12.5% of the class are both honor students and athletes

Step-by-step explanation:

The Class has a total of 160 students. Of those 160 students, 80 are neither athletes or honor students. That leaves 80 students left.

Out of those 80 students, 60 students are athletes and 40 students are honor students. since 60+40 = 100 , that means that 20 students are BOTH athletes and honor students. We can now calculate what percentage 20 is in a class of 160 students.

$\frac{20}{160} = 0.125$

0.125*100 = 12.5%  ........we multiply by 100 to turn the decimal into a percent.

So we can see that 12.5% of the class are both honor students and athletes.

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