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Lunna [17]
2 years ago
10

In the system –12c + 3d = 6 and –3c + 6d = –9, which expression could you use for substitution?

Mathematics
1 answer:
inna [77]2 years ago
8 0

–12c + 3d = 6

12c = 3d - 6

c = 1/4 d - 1/2

Answer is

C. c = 1/4 d – 1/2

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ava gathered data about the age of runners and the time it took them to complete a 5K race and half marathon. Her data is displa
Serggg [28]

Answer: B.

Step-by-step explanation:

I wrote my answer in the comments, but I’ll say it again; the answer is likely B. Because the other options are not very relevant. B. Is the option most likely to be disputed on. I do not know if this is the answer however, but this was what I thought.

7 0
2 years ago
Sal exercised by stretching and jogging 5 days last week.
pashok25 [27]
So sal stretched for about 5 min. each day in 5 days and he jogged for about 43 min ..how??
I divided 215 to 5 and I got 43 min. and how did I get 215 well 240 minus 25 min is 215

and elena she stretches for 75 min in the whole 5 days total and 300 minus 75 is 225. then 225 divided by 15 is 15

Sam jogged for 43 min a day and elena jogged for 15 min a day
I hope this helps :)
4 0
2 years ago
Hazel needs to get to her granddaughter's house by taking an airplane and a rental car. She travels 900 miles by plane and 250 m
Arisa [49]

Answer:

50 pmh

Step-by-step explanation:

Distance traveled by plane = 900 miles

Distance traveled by car = 250 miles

Let the speed of the car is c. The plane travels 250 mph faster than the car, so speed of the plane will be c + 250

Let the time taken to travel on car is t. She traveled 2 hours more on car the she rode on plane. This means she consumed 2 hours less time on plane. So the time spent on plane will be t - 2 hours.

Distance = Speed x Time

For Plane, the equation will be:

900 = (c + 250)(t - 2)                                    <u>Equation 1</u>

Likewise, the equation for car will be:

250 = ct

From here, t = 250/c

Using this value in Equation 1, we get:

900= (c + 250)(\frac{250}{c} -2)\\\\ 900=250 +\frac{62500}{c}-2c-500\\\\ 1150=\frac{62500}{c}-2c\\\\ 1150c=62500-2c^{2}\\\\ 2c^{2}+1150c-62500=0\\\\ \text{Using the quadratic formula, we get}\\\\ c=\frac{-1150\pm \sqrt{1150^{2}-4(2)(-62500)} }{2(2)}\\\\ c = -625, 50

Since value of speed cannot be negative, we only consider the positive value. So from here we can conclude that the speed of the car was 50 mph

3 0
2 years ago
craig spent $27 to buy 3 calendars. the next day, he spent another $18 for more calendars. Each calendar cost the same amount. H
Maslowich

Answer:

She bought 5 calendars.

Step-by-step explanation:

Let Craig bough x calendars.

The cost of 3 calendars is $27.

Hence, the cost of 1 calendar is 27/3 = $9

Now, it has been given that she spent another $18 for more calendars. And we have calculated that cost of 1 calendar is $9.

Hence, in $18 she could buy 2 more calendars.

Therefore, the number of calendars she bought is given by

3 + 2

= 5

She bought 5 calendars

8 0
2 years ago
A principal of $5,350 is placed in an account that earns 3.5% interest. If the interest is compounded annually, how much money w
neonofarm [45]

we know that  

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=4\ years\\ P=\$5,350\\ r=0.035\\n=1  

substitute in the formula above  

A=5,350(1+\frac{0.035}{1})^{1*4}=\$6,139.25

therefore

<u>the answer is the option D </u>

\$6,139.25

7 0
2 years ago
Read 2 more answers
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