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2 years ago

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please help A salesperson earns a salary of $800 per month plus 2% of the sales. Which inequality represents the total sales if

the salesperson is to have a monthly income of at least $1600?

2 answers:

Lisa [10]2 years ago

8 0

X - the total sales
800 + 0.02 x ≥ 1600
0.02 x ≥ 1600 - 800
0.02 x ≥ 800
x ≥ 800 : 0.02
x ≥ 40,000
The total sales must be at least $40,000.

LiRa [457]2 years ago

6 0

Let x= total sales per month

800 + 0.02x ≥ 1600
800 + 0.02x - 800 ≥ 1600 -800
0.02x ≥ 800
0.02x/0.02 ≥ 800/0.02
x ≥ 40000 USD

The monthly total sales should be greater than or equal to 40000 dollars to have a monthly income of at least 1600 dollars.

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Answer with Step-by-step explanation:

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2 years ago

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<em><u>The intervals included in solution are:</u></em>

$\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0$

<em><u>Solution:</u></em>

Given that,

A boat tour guide expects his tour to travel at a rate of x mph on the first leg of the trip

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$\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}$

<em><u>We have to solve the inequality</u></em>

$\frac{1}{x} + \frac{1}{x} - 10\geq \frac{2}{24}\\\\\frac{2}{x} - 10\geq \frac{2}{24}$

$\mathrm{Subtract\:}\frac{2}{24}\mathrm{\:from\:both\:sides}\\\\\frac{2}{x}-10-\frac{2}{24}\ge \frac{2}{24}-\frac{2}{24}\\\\Simplify\\\\\frac{2}{x}-10-\frac{2}{24}\ge \:0$

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$\mathrm{Multiply\:both\:sides\:by\:}24\\\\\frac{24\left(48-242x\right)}{24x}\ge \:0\cdot \:24\\\\Simplify\\\\\frac{48-242x}{x}\ge \:0\\\\Factor\ common\ terms\\\\\frac{-2\left(121x-24\right)}{x}\ge \:0\\\\\mathrm{Multiply\:both\:sides\:by\:}-1\mathrm{\:\left(reverse\:the\:inequality\right)}$

When we multiply or divide both sides by negative number, then we must flip the inequality sign

$\frac{\left(-2\left(121x-24\right)\right)\left(-1\right)}{x}\le \:0\cdot \left(-1\right)\\\\\frac{2\left(121x-24\right)}{x}\le \:0\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{\frac{2\left(121x-24\right)}{x}}{2}\le \frac{0}{2}\\\\Simplify\\\\\frac{121x-24}{x}\le \:0$

$\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{121x-24}{x}\\$

This is attached as figure below

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$\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:\le \:\:0\\\\0$

<em><u>Therefore, solution set is given as</u></em>:

$\frac{1}{x} + \frac{1}{x}-10\ge \frac{2}{24}\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:0$

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vampirchik [111]

Answer:

see the explanation

Step-by-step explanation:

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2 years ago

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andriy [413]

Answer: $76.19\%$

Step-by-step explanation:

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8 0

2 years ago