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djverab [1.8K]
2 years ago
9

6 wrestlers compete in a competition. if each wrestler wrestles one match with each other wrestler, what are the total numbers o

f matches?
Mathematics
2 answers:
PolarNik [594]2 years ago
3 0

The total number of wrestlers are 6 and each have to wrestle each other wrestler only once.

It means, the first wrestler have 5 opponent, second have 4 opponents , third have three oponenets , fourth have two opponents and the fifth have only one opponent.

So the total number of matches = 5+4+3+2+1 =15

Ronch [10]2 years ago
3 0

Answer:

5 wrestling matches

Step-by-step explanation:

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Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right
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Step-by-step explanation:

Let us revise the rules in the right angle triangle when we draw the perpendicular from the right angle to the hypotenuse

In triangle ABC

Angle B is a right angle  and AC is the hypotenuse

BD ⊥ AC  ⇒ perpendicular from the right angle to the hypotenuse

  • (AB)² = AD × AC
  • (BC)² = CD × AC
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In Δ SRQ

∵ ∠SRQ is a right angle

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∵ RT ⊥ SQ

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By using Pythagoras theorem in Δ SRQ

∵ (SR)² + (RQ)² = (SQ)²

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- Take √ for both sides

∴ SR = 15 units

The length of the line segment SR is 15 units

Learn more:

You can learn more about right triangles in brainly.com/question/1238144

#LearnwithBrainly

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