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elixir [45]
2 years ago
10

Consider five independently assorting gene pairs, a/a, b/b, c/c, d/d and e/e, where each demonstrates complete dominance (a_, b_

, c_, d_, and e_) and recessiveness (aa, bb, cc, dd and ee). an individual with genotype aabbccddee is crossed to an individual with genotype aabbccddee. what is the probability of obtaining an offspring with genotype aabbccddee?
Biology
1 answer:
valina [46]2 years ago
4 0
100% because the genotypes are the same
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The answer is B

Explanation:

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The diagram represents a dihybrid cross between two pea plants heterozygous for both seed color and seed shape. mc021-1.jpg What
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The correct answer is 9:3:3:1

When two homozygotes for two traits cross, the phenotypic ratio of the offspring is 9:3:3:1 ( unless other factors like epistatic interaction change the inheritance model).
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7 0
1 year ago
In humans, black hair (B) is dominant over red hair (b) and having six fingers (F) is dominant over having five fingers (f). Sal
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Answer:

Genotype  & Phenotype  

BbFf  - 4  

bbFf - 4

Bbff - 4

bbff- 4

Phenotype  

BbFf – Black Hair with six fingers

bbFf – red hair with six fingers

Bbff – Black hair with five fingers

Bbff – red hair with five fingers

Explanation:

Given

Black hair allele is represented by "B"

Red hair allele is represented by "b"

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Trait of having five fingers is represented by "f"

Also , B is dominant over b and F is dominant over f

Genotype of sally having black hair and five fingers when her father has red hair is  Bbff

Genotype fo Bill having red hair and six fingers  when his mother had five fingers is bbFf

Bbff * bbFf

Bf         bf         Bf         bf

bF BbFf bbFf BbFf bbFf

bf Bbff         bbff         Bbff         bbff

bF BbFf bbFf BbFf bbFf

bf Bbff         bbff         Bbff         bbff

Genotype  & Phenotype  

BbFf  - 4  

bbFf - 4

Bbff - 4

bbff- 4

Phenotype  

BbFf – Black Hair with six fingers

bbFf – red hair with six fingers

Bbff – Black hair with five fingers

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