It represents a decomposition reaction because one reactant breaks apart and forms two products.
Explanation:
The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.
In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.
XY → X + Y
- Decomposition or cracking is the formation of two or more products from a single reactant.
- The break down of a compound into individual atoms or molecules falls into this category.
- The extreme instability of a compound drives such a reaction.
- The products is usually stable or it can dissociate further till it is stable.
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Using the combined gas law, where PV/T = constant, we first solve for PV/T for the initial conditions: (4.50 atm)(36.0 mL)/(10.0 + 273.15 K) = 0.57213.
Remember to use absolute temperature.
For the final conditions: (3.50 atm)(85.0 mL)/T = 297.5/T
Since these must equal, 0.57213 = 297.5/T
T = 519.98 K
Subtracting 273.15 gives 246.83 degC.
Answer : Option 3) Wave/Particle duality.
Explanation : The experiment on discovery of photoelectric effect revealed about the photoelectrons of light that can behave as particle or waves.
The photoelectric effect is observed when the emission of electrons or other free carriers occurs on shining a light radiation on a material. The electrons emitted from this can be called photo electrons. These photoelectrons may behave as wave or particle in duality which holds that light and matter exhibit properties of both waves and of particles.
Sucrose is a non ionic compound. It does liberates ion when dissolved in water unlike NaCl or other salts which dissolve in water and produce respective cations and anions.
Thus if any amount of sucrose is dissolved in water, it will form non ionic aqueous solution (it will dissolve completely). Thus sucrose solution being non electrolytic will not conduct electricity in aqueous solution.
the bulb will not light up as sucrose will remain in molecular form only
Answer:

Explanation:
Hello,
In this case, considering that the by-mass percent of water is:

Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:

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