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Tamiku [17]
2 years ago
10

Jane made this picture to represent a chemical reaction: Two circles, one white and the other gray are shown on the left. A smal

l portion of the two circles overlap and the label below the circles is XY. An arrow pointing right is shown on the right of the overlapping circles. There are two circles on the right of the arrow, one white and the other gray, and there is a plus sign between them. The white circle is labeled X and the gray circle is labeled Y.
Which of the following statements best explains the type of chemical reaction represented by Jane's picture?

It represents a synthesis reaction because one combined reactant forms multiple products.
It represents a synthesis reaction because the same atoms are present in the reactants and products.
It represents a decomposition reaction because one reactant breaks apart and forms two products.
It represents a decomposition reaction because the total mass of the products is less than the mass of the reactant.

Chemistry
2 answers:
7nadin3 [17]2 years ago
8 0

It represents a decomposition reaction because one reactant breaks apart and forms two products.

Explanation:

The type of chemical reaction depicted by Jane represents a decomposition reaction because on reactant breaks apart and forms two products.

In this reaction XY breaks apart to form X and Y. This is a decomposition reaction.

                     XY   →   X + Y

  • Decomposition or cracking is the formation of two or more products from a single reactant.
  • The break down of a compound into individual atoms or molecules falls into this category.
  • The extreme instability of a compound drives such a reaction.
  • The products is usually stable or it can dissociate further till it is stable.

      Find the image attached for more explanation:

Learn more:

Thermal decomposition brainly.com/question/11181911

#learnwithBrainly

dimaraw [331]2 years ago
3 0

Answer:

It represents a decomposition reaction because one reactant breaks apart and forms two products.

Explanation:

took the test

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If an aqueous solution of urea n2h4co is 26% by mass and has density of 1.07 g/ml, calculate the molality of urea in the soln
Ksju [112]
Answer is: molality of urea is 5.84 m.

If we use 100 mL of solution:
d(solution) = 1.07 g/mL.
m(solution) = 1.07 g/mL · 100 mL.
m(solution) = 107 g.
ω(N₂H₄CO) = 26% ÷ 100% = 0.26.
m(N₂H₄CO) = m(solution) · ω(N₂H₄CO).
m(N₂H₄CO) = 107 g · 0.26.
m(N₂H₄CO) = 27.82 g.
1) calculate amount of urea:
n(N₂H₄CO) = m(N₂H₄CO) ÷ M(N₂H₄CO).
n(N₂H₄CO) = 27.82 g ÷ 60.06 g/mol.
n(N₂H₄CO) = 0.463 mol; amount of substance.
2) calculate mass of water:
m(H₂O) = 107 g - 27.82 g.
m(H₂O) = 79.18 g ÷ 1000 g/kg.
m(H₂O) = 0.07918 kg.
3) calculate molality:
b = n(N₂H₄CO) ÷ m(H₂O).
b = 0.463 mol ÷ 0.07918 kg.
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<span>MnO2 + 4 HCl ---> MnCl2 + Cl2 + 2 H2O. 
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7 0
2 years ago
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2.00 g of an unknown gas at STP fills a 500. mL flask. What is the molar mass of the gas?
otez555 [7]

Answer:

100g/mol

Explanation:

Given parameters:

Mass of unknown gas  = 2g

Volume of gas in flask  = 500mL  = 0.5dm³

Unknown:

Molar mass of gas = ?

Solution:

Since we know the gas is at STP;  

        1 mole of substance occupies 22.4dm³ of space at STP

    Therefore,

            0.5dm³ will have  0.02mole at STP

                     

Now;

   Number of moles  = \frac{mass}{molar mass}  

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4 0
2 years ago
The melting point of water is 0°C at 1 atm pressure because under these conditions:
Tems11 [23]

Answer:

The correct answer is option C, that is, ΔS and ΔSsurr for the process H2O (s) ⇒ H2O(l) are equal in magnitude and opposite in sign.

Explanation:

The temperature at which solid state of water get transformed into liquid state is termed as the melting point of 0 °C. It can be shown by the reaction:  

H2O (s) ⇒ H2O (l)

The degree of randomness of a molecule is known as entropy. With the transformation of ice into liquid state, there is an increase in randomness. Thus, the value of entropy becomes positive as shown:  

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Therefore, the value of entropy change is positive.  

Now the value of entropy for surrounding ΔSsurr will be,  

ΔSsurr = -ΔHfusion/T  

= -6012 j/mol/273

= -22.0 J/molK

Hence, the value of ΔSsurr and ΔSsys exhibit same magnitude with opposite sign.  

8 0
2 years ago
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