<h2>
Answer:</h2>
<u>The correct option is </u><u>The letter on the front will be N. The letter on the back will be L.
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<h2>
Step-by-step explanation:</h2>
When we fold the given net, we will get Q,P,M and N on sides. Side M will come to the top, side Q on the right side, side P on the left and side O on the bottom. The side which comes to the front will be N of the observer and similarly the side L will come to the back of the rectangular prism.
Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
2+3.25g=y
G would be the independent variable, which means the total cost would depend on it since it depends on the number of games you bowl. Y could be any variable, such as T or C.
2+3.25g=y
Answer:
0.8759 is the probability that no less than 4 of the entry forms will include an order.
Step-by-step explanation:
We are given the following information:
We treat subscription order with an entry form as a success.
P(subscription order with an entry form) = 0.4
Then the number subscription order with an entry form follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 14
We have to evaluate:
0.8759 is the probability that no less than 4 of the entry forms will include an order.
You would multiply by 1.7