The mass of three samples are 0.12 g, 1.8 g and 0.562 g. (given)
During addition (mathematical operation) of significant figures following rules are followed:
1. The number of significant figures are counted.
2. Addition is done.
3. Round the answer to the least number of decimal places.
Following the above rules, the addition of mass of the three samples is as follows:
Hence, is the combined mass of all the three samples.
Answer:
K = 6.5 × 10⁻⁶
Explanation:
C₅H₆O₃ ⇄ C₂H₆ + 3CO
Use PV=nRT to find the initial pressure of C₅H₆O₃
P (2.50) = (0.0493) (0.08206) (473)
P = 0.78atm
C₅H₆O₃ ⇄ C₂H₆ + 3CO
0.78atm 0 0
0.78 - x x 3x
1.63atm = 0.78 - x + x + 3x
P(total) = 0.288atm
C₅H₆O₃ = 0.78 - 0.288
= 0.489atm
C₂H₆ = 0.288atm
CO = 0.846atm
= 0.379
= 6.5 × 10⁻⁶
Answer: The boron atom of has three hybrid orbitals
Explanation: Hybridization of the molecule can be calculated by:
.....(1)
where,
V = number of valence electrons in the central metal atom
H = number of monovalent atoms
C = cationic charge
A = anionic charge
Here, electronic configuration of B =
Number of valence electrons = 3
Number of monovalent atoms = 3
Cationic charge = 0
Anionic charge = 0
Putting these values in equation 1, we get
As the Hybridization is 3, which means that boron has 3 hybrid orbitals.