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LekaFEV [45]
2 years ago
14

If there is a loss of 5.63 x 10 -7 kg of mass in a nuclear reaction, how many joules of energy would be released? Recall that C

equals 3 times 108 m / s.
Chemistry
1 answer:
ira [324]2 years ago
6 0
5.07x10^10 may be right but i dunoo know bro 
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Using the idea of electronegativity difference for predicting polarity of bonds and considering the shape of the following molec
Zinaida [17]
See electronegativity is the tendency of an atom to gain an electron and flourine with a valecy of one and a vey small size is the most electronegetive because its orbitals are quite closed to the nucleus and hence the attraction is quite strong so it can attract an electron.the question that arises is that some smaller atoms should be more electronegetive as they are closer to the nucleus but it need more energy for them as compared to flourine to complete their octet. now polarity increases when two atoms of quite different sizes form a compound ... the more electronegetive atom will always attract the bond pair forming a negetive charge on it and positive on the less electroneg. one and polarity increases with electronegetivity of the anion.now as your question says 
<span>5=I2.. because both the atoms are same there wont be permanent polarity </span>
<span>4=HI iodine is the least electronegetive of all the halogens due to its large size,electronegetivity decreases down the group </span>
<span>3=HBr bromine is the 2nd largest halogen </span>
<span>2=HCl chlorine is the 3rd largest halogen </span>
<span>1=HF fluorine is the smallest halogen making and hence makes the most polar</span>
8 0
2 years ago
Explain how a solution can be both dilute and saturated.
svlad2 [7]
Dilution<span> is when you decrease the concentration of a </span>solution<span> by adding a solvent. As a result, if you want to </span>dilute<span> salt water, just add water. ... Add more solute until it quits dissolving. That point at which a solute quits dissolving is the point at which it's </span>saturated<span>.</span>
4 0
2 years ago
Read 2 more answers
A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted?
Kay [80]

Answer:

The mass of sodium that reacted is 230 grams

Explanation:

The balance equation of the reaction is first written .

sodium = Na

Chlorine = Cl2

sodium chloride = NaCl

2Na + Cl2 → 2NaCl

from the balance equation we calculate the molar mass involve in the reaction

Molar mass of sodium from the equation = 23(2) = 46 g

molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g

If 46g of sodium is in 117 g of sodium chloride

? gram will be in 585 g of sodium chloride

cross multiply

46 × 585/117 = 26910/117  = 230 g

The mass of sodium that reacted is 230 grams

5 0
2 years ago
Draw the structure of a compound with molecular formula c5h12 that exhibits only one kind of proton (all 12 protons are chemical
Sophie [7]
The middle carbon is 4-degree since it is attached to 4 carbons. All other carbons are 1-degree since they are attached to only 1 carbon. 

Hydrogens attached with 1-degree carbon are all same. Hydrogen are often refereed to as protons. No carbon is attached to 4-degree carbon. So all hydrogens in this structure are same.

This structure is called  NeoPentane

4 0
2 years ago
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
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