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photoshop1234 [79]
2 years ago
9

Solve: 5x(8-4) divide 4-2=

Mathematics
1 answer:
nataly862011 [7]2 years ago
8 0

5x(8 - 4)/4 - 2

Remember to follow PEMDAS.

First, subtract 8 and 4

8 - 4 = 4

5x(4)/4 - 2

Next, follow the left -> right rule, and multiply 5x and 4

5x(4) = 20x

Divide by 4

20x/4 = 5x

Finally, note that one has a variable, and the other has a constant, and so you cannot combine.

5x - 2 is your answer

hope this helps

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A hair stylist knows that 87% of her customers get a haircut and 40% get their hair colored on a regular basis. Of the customers
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Answer:

Okay so!

Step-by-step explanation:

for a cut that's .87 and for a color that is .24 so you multiply them together to get the probability for the color which is

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1 year ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
A map of a rectangular park has a length of 4 inches and a width of 6 inches. It uses a scale of 1 inch for every 30 Miles. What
MakcuM [25]

Answer:

The actual area 21600 miles²

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A drawing that shows a real object with accurate sizes reduced or

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- Drawing scale is a ratio between the drawing length and the

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*<em> Lets solve the problem</em>

- A map of a rectangular park has a length of 4 inches and a width

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∴ The drawing dimensions are:

# length = 4 inches

# width = 6 inches

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∴ The scale drawing is 1 : 30

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∵ The scale drawing is 1 : 30

∵ The length = 4 inches and the width = 6 inches

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∴  1        :        30

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   6       :  actual width

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∴ Actual Width = 180 miles

∴ The actual dimensions are 120 miles and 180 miles

∵ The area of any rectangle = length × width

∴ The actual area = 120 × 180 = 21600

∴ The actual area 21600 miles²

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The answer is 8 sugar cubes
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