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2 years ago

3

The ratio of the concentration of a(n) over describes the proportions of a weak acid necessary to satisfy the

henderson-hasselbalch equation.

2 answers:

Vladimir79 [104]2 years ago

6 0

The pH of a buffer is calculated using Hendersen Hassalbalch's equation

pH = pKa + log [salt] / [acid]

thus ratio of concentration of conjugate base or species which can accept proton over a proton donor or conjugate acid describes the proportion of weak acid.

The solution of weak acid with its salt of strong base results into formation of a buffer, solution which resists change in pH on addition of small amount of strong acid or strong base

svp [43]2 years ago

3 0

Answer:

The ratio of the concentration of a <em><u>conjugate base</u></em> over <em><u>weak acid </u></em>describes the proportions of a weak acid necessary to satisfy the Henderson-Hasselbalch equation.

Explanation:

The Henderson Hesselbach equation is given as:

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

pH = potential of H

$pK_a=-\log [K_a]$

$K_a$ =Dissociation constant

[Salt] = Concentration of salt

[Acid] = Concentration of acid

Or it can also be represented as:

WeaK acid $\rightleftharpoons H^+$ + Conjugate base

$pH=pK_a+\log \frac{[\text{conjugate base}]}{[\text{weak acid}]}$

[conjugate base] = Concentration of conjugate base formed from the dissociation of weak acid.

[weak acid] = Concentration of weak acid.

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Answer:

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Explanation:

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On the other hand, the frequency of a wave is the number of periods in unit time. $1\rm \; Hz$ means one oscillation per second. The frequency of this particular wave is $\rm 6.83\times 10^{14}\; Hz$ . In other words, there are $6.83\times 10^{14}$ oscillations in each second.

The period of oscillation will be equal to

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In that period of time, a beam of light in vacuum would have traveled

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2 years ago

Are The Reactions Of Ordinary Molecular Hydrogen Slow Or Rapid ? Why ?

olchik [2.2K]

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An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or

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2 years ago

Read 2 more answers

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

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2 years ago

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Bas_tet [7]

<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>

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2 years ago