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Marrrta [24]
2 years ago
10

There is 1 in. of water in a pool. The water level is increasing at 0.75 in./min . Which linear equation represents the total de

pth of the water, in inches, after x minutes?
A. 1+y=0.75x

B. y=0.75x+1

C. y=0.75x

D. x=0.75y
Mathematics
2 answers:
Alex2 years ago
8 0

Answer:

B. y=0.75x+1

Step-by-step explanation:

Initial level of pool, y_i=1 \ inch.

The rate of increase in level of water, \dfrac{dy}{dt}=0.75\ inch/min.

Now, to find relation between depth  and time .

From above equation, dy=0.75\ dt.

Now at time = 0 min depth is 1 inch and at any time t=x min and depth=y inch.

Therefore, \int\limits^y_1 \, dy=0.75\int\limits^x_0 \, dt.

Integrating both sides,

We get y|_1^y=0.75\ t|_0^x

y-1=0.75x

y=0.75x+1

Therefore , correct answer is B.

Hence, it is the required solution.

yan [13]2 years ago
4 0
I think it is B. y=0.75x+1. I think that 1 in. of water in a pool is the y-intercept.
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The correct option is;

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The Leaning Tower of Pisa in Italy was built between 1173 and 1350. A. Write an equation in slope-intercept form for the yellow
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Answer:

The answer is below

Step-by-step explanation:

From the image of the leaning tower of Pisa, we can see that it passes through the point (7.75, 0) and (10.75, 42).

a) The equation of a line in slope intercept form is given by y = mx + b, where m is the slope and b is the intercept. Also, the equation of line passing through

(x_1,y_1)\ and\ (x_2,y_2)\ is:\\\\y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)

Hence since it passes through  (7.75, 0) and (10.75, 42), the equation is:

y-0=\frac{42-0}{10.75-7.75} (x-7.75)\\\\y=14(x-7.75)\\\\y=14x-108.5

b) When the tower is 56 meters tall, i.e. y = 56, we need to find the value of x:

y = 14x - 108.5

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Data from 14 cities were combined for a​ 20-year period, and the total 280 ​city-years included a total of 107 homicides. After
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Answer:

P(0) =  0.6825

P(1) = 0.2607

Step-by-step explanation:

From the given information, the number of homicide is 107 and the total number of homicides per city –year is 280.

Let us denote the number of homicides per city-year as X.

The mean value, X is calculated as:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}  

Mean=   107/280 = 0.382  

The mean number of homicides per city- year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. The probability that zero homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

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P(X=0) = 0.6825

Thus, the probability that zero homicides P(0) is 0.6825.

b. The probability that one homicides is obtained is as below:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}  

P(X=1) =  e  −0.382  (0.382)¹​/1  

= (0.6825)(0.382)/1  

P(X=1) = 0.2607

Thus, the probability that zero homicides P(0) is 0.2607.

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