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Nadusha1986 [10]

2 years ago

12

Travant is planning a garden that will cover 1,600 square yards. he wants the ratio of space planting with flowers to space plan

ted with vegetables to be 3:5. how many square yards of flowers will travant have?
could you show the working

2 answers:

expeople1 [14]2 years ago

6 0

Area covered by flowers is X
Area covered by vegetables is Y

X/Y = 3/5
5X = 3Y

X + Y = 1600
X + 5/3X = 1600
8/3X = 1600

X = 1600 * 3 / 8 = 600 Sq Yards

Novosadov [1.4K]2 years ago

5 0

3+5 =8 then divide 1600 by
8 =200 then multiply 3 x 200 = 600

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Answer:

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$N = 209 \ unites$

b

$N_{max} = 249$

Step-by-step explanation:

From the question we are told that

The daily demand is $d = 7/day$

The standard deviation is $\sigma = 3 /day$

The service probability is $s = 95\% = 0.95$

The number of chips in the inventory is $k = 40$

The number of days in his monthly is $T = 30 \ days$

The lead time is $L = 4$

Generally the number he should order (optimal order ) is mathematically represented as

$N = d(L + T)+(\sigma_{T + L} * z) -k$

Here $\sigma__{T+L }}$ is the monthly standard deviation which is mathematically evaluated as

$\sigma__{T + L}} = \sqrt{(T + L) * 1^2}$

=> $\sigma__{T + L}} = \sqrt{34}$

=> $\sigma__{T+L}} = 5.83$

Also z-value for the 95% service probability from the z-table is 1.96

So

$N = 7 * (30 +4 ) + (1.96 * 5.83) - 40$

=> $N = 209 \ unites$

For the maximum order quantity k = 0

So

$N_{max} = d(L + T)+(\sigma_{T + L} * z) -0$

=> $N_{max} = 7 * (30 +4 ) + (1.96 * 5.83) - 0$

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2 years ago

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