Question

How many atoms are in 80.2 grams of Calcium?

Answer 1

Answer:

There are $1.207\times 10^{24} atoms$ in 80.2 grams of calcium.

Explanation:

Atomic mass of calcium = 40 g/mol

Mass of calcium given = 80.2 g

Moles of calcium = $\frac{80.2 g}{40 g/mol}=2.005 mol$

1 mol = $N_A=6.022\times 10^{23}$ atoms/ molecules, ions

Number of atoms of calcium in 2.005 moles of calcium:

$2.005 \times 6.022\times 10^{23}=1.207\times 10^{24} atoms$

There are $1.207\times 10^{24} atoms$ in 80.2 grams of calcium.

Answer 2

Calculate the number of atoms in 80.2 g of calcium metal. ___________
Ca: 1 x 40.1 = 40.1 g/mol (80.2 g Ca)/(40.1 g/mol) = 2 mol x (6.02 x 1023 atoms/mol) = 1.2 x 1024 atoms.
3.