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sp2606 [1]
2 years ago
11

What is the standard metric unit of power

Physics
1 answer:
mash [69]2 years ago
4 0

[ Power ]  =  [ energy ] / [ time ]

SI unit of energy = Joule
SI unit of time = second

Unit of power  =  (1 joule) / (1 second)  =  1 <em>watt</em>


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The CBR method of flexible pavement design gives an idea about the:
marta [7]

Answer:

A. quality of road-making material

Explanation:

The CBR method of flexible pavement design gives an idea about the:

A. quality of road-making material

B. traffic intensities

C. characteristics of soil

D. All of the above

The California Bearing Ratio (CBR) test is a penetration test used to evaluate the subgrade strength of roads and pavements. The results of these tests are used with the curves to determine the thickness of pavement and its component layers. it is the measure of the resistance of a material against the penetration of a standard plunger.

This can be used to determine the quality of road making material. CBR is expressed as the percentage of the actual load to the standard load.

3 0
2 years ago
Rod A and rod B are cylindrical rods made of the same metal. amd they differ only in size. Rod B has double the length and doubl
Sever21 [200]

Answer:

I believe the answer for this question is D

Explanation:

I hope this helps and is correct

6 0
2 years ago
Read 2 more answers
1. A diffraction grating with 5.000 x 103 lines/cm is used to examine the sodium
Nuetrik [128]

Answer:

0.0002°, 0.1691°, 0.338°

Explanation:

Difference between the two line = 5.97 * 10-⁸m

d = 1 / N

N = 5.0 * 10³

d = 2.0 * 10⁴m

nL = Nsin¤

For first order

588.995 * 10-⁹ = 2.0 * 10-⁴ sin ¤

Sin¤ = 2.944*10-³

¤ = sin-¹ 0.002944

¤ = 0.1687°

First order ¤ =

Sin-¹(589.592*-⁹ / 2.0 * 10-⁴)

Sin-¹ (0.002947) = 0.1689°

Angular separation = 0.1689 - 0.1687 = 0.0002°

Second order ¤ = sin-¹ [2 (589.59*10-⁹ / 2.0*10-⁴)] = sin-¹ (0.005895)

Second order ¤ = 0.3378°

Angular difference = 0.3378° - 0.1687° = 0.1691°

Third order ¤ = sin-¹ [3(589.59*10-⁹ /2.0*10-⁴] = 0.5067°

Angular difference = 0.5067° - 0.1687° = 0.338°

7 1
2 years ago
Read 2 more answers
A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by
Delicious77 [7]

Answer:

W = -510.98J

Explanation:

Force = 43N, 61° SW

Displacement = 12m, 22° NE

Work done is given as:

W = F*d*cosA

where A = angle between force and displacement.

Angle between force and displacement, A = 61 + 90 + 22 = 172°

W = 43 * 12 * cos172

W = -510.98J

The negative sign shows that the work done is in the opposite direction of the force applied to it.

6 0
2 years ago
A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and
snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m

There is a rate of change of the perpendicular component of momentum.

Centripetal force acts always towards the center.

We need to calculate the magnitude of the rate of change of the child's momentum

Using formula of momentum

\dfrac{dp}{dt}=F

\dfrac{dP}{dt}=\dfrac{mv^2}{r}

Put the value into the formula

\dfrac{dP}{dt}=\dfrac{27\times10^2}{3.40}

\dfrac{dP}{dt}=794.11\ N

Hence, The magnitude of the rate of change of the child's momentum is 794.11 N.

7 0
2 years ago
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