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2 years ago

A veterinarian treated 7 dogs, 13 cats, 4 horses, and 3 ferrets. What percentage of his patients were small animals?

1 answer:

6 0

As per your defention, horses are the only thing considered "not small". To find the percentage, you take the number of what you are trying to find the percentage of divided by the total number.

So, 7 dogs + 13 cats + 3 ferrets = 23 Small animals

7 dogs + 13 cats + 3 ferrets + 4 horses = 27 total animals.

So,

$\frac{23}{27}*100$

The reason we multiply by 100 is because the division gives us a decimal, and a percentage is a part out of 100.

So by doing the calculation we get

85.18%

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Find the CP of the following Sp=Rs 851 , Loss=8%

elena55 [62]

<h3>Selling Price = Rs. 851</h3>

<h3>FORMULA = 100/100 - LOSS % × SP</h3>

<h3>HOPE IT HELPS YOU.</h3>

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1 year ago

Rusty is training for a triathlon. He runs 4miles for every 9 miles he bikes. At the end of his training, he has run o total of

Neporo4naja [7]

Answer:

Rusty bikes for 207 miles

Step-by-step explanation:

Because 23 times 4 gives you 92 so you have to also multipy 9 by 23 gives you 207 miles. So Rusty biked for 207 miles. Hoped this helped.

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2 years ago

Leonel runs on different trails near his home for exercise. uses of positioning device to record how far from home he is when he

anygoal [31]

Answer:

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1 year ago

Two friends race against each other in 100-meter and 800-meter races. Of the 200 races they ran this year, the wins, losses, and

sveta [45]

1. <span>What percentage of all the races are ties?
If</span>The chance for the race become tie is 10% for 100m and 25% for 800m. Assuming that the 200 race is divided equally, then there would be 100 race of 100-m and 100 race of 800-m.
The number of the event of ties would be:
(100*10% + 100*25%)/ 200= 35/200= 17.5%

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1 year ago

INTERPRETATIONS OF THE DEFINITE INTEGRAL: Solar photovoltaic (PV) cells are the world’s fastest growing energy source. In year (

bezimeni [28]

Answer:

31.747 GW

Step-by-step explanation:

The total cell capacity (C) manufactured in the time period is the integral of the rate of manufacture. So, we have ...

$C=\displaystyle\int\limits^3_0 {3.7e^{0.61t}} \, dt=\frac{3.7}{0.61}(e^{0.61\cdot 3}-1)\approx 31.747 \quad\text{GW}$

About 31.747 GW of generating capacity was manufactured in that time interval.

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1 year ago