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allsm [11]
2 years ago
10

INTERPRETATIONS OF THE DEFINITE INTEGRAL: Solar photovoltaic (PV) cells are the world’s fastest growing energy source. In year (

t) since 2007, PV cells were manufactured worldwide at a rate of S=3.7e^(0.61t) gigawatts per year. Estimate the total solar energy-generating capacity of the PV cells manufactured between 2007 and 2010. Round your answer to 3 decimal places.
Mathematics
1 answer:
bezimeni [28]2 years ago
7 0

Answer:

  31.747 GW

Step-by-step explanation:

The total cell capacity (C) manufactured in the time period is the integral of the rate of manufacture. So, we have ...

  C=\displaystyle\int\limits^3_0 {3.7e^{0.61t}} \, dt=\frac{3.7}{0.61}(e^{0.61\cdot 3}-1)\approx 31.747 \quad\text{GW}

About 31.747 GW of generating capacity was manufactured in that time interval.

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Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat
yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0
2 years ago
What is happening to the graph when the x-values are between 4 and 8
VashaNatasha [74]
The numbers are going down
5 0
2 years ago
Read 2 more answers
Suppose that W and X are point on the number line. If WX= 10 and X lies at -7, where could W be located? If there is more than o
olchik [2.2K]
17 I think is correct
3 0
2 years ago
Which is the graph of the linear inequality x – 2y > –6?
Zina [86]

Answer:

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded.

Step-by-step explanation:

The first step is writing in the general form of the first order equation

y = f(x) or y > f(x) or y < f(x)

And

f(x) = ax + b

In which a is the slope.

We have that:

x - 2y > -6

-2y > -6 - x

When multiplying by -1, the signal changes, from > to <

2y < x + 6

y < 0.5x + 3

The slope is positive, since 0.5 is positive.

Since it is y lesser than, it is everything below and to the right of f(x) is painted.

The line is dashed because this is just lesser, not lesser or equal.

The correct answer is:

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 4, 2) and (4, 4). Everything below and to the right of the line is shaded.

8 0
2 years ago
Read 2 more answers
Use the graph of f below. Assume the entire function is graphed below.<br> Find the domain
enot [183]

ANSWER

The domain of the function is

- 3 \leqslant x \leqslant 6

or

[-3,6]

EXPLANATION

The domain of a function refers to the values of x for which the function is defined.

From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).

Therefore the function is defined for x=-3 to x=6.

Hence the domain of the function is

- 3 \leqslant x \leqslant 6

or

[-3,6]

5 0
2 years ago
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