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svp [43]
1 year ago
10

If a container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep, how many boxes are in the container?

Mathematics
2 answers:
aleksandrvk [35]1 year ago
8 0
<h2>Answer:</h2>

The total  number of boxes that are in the container are:

                              30 boxes.

<h2>Step-by-step explanation:</h2>

It is given that:

     A container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep.

This means that the total number of boxes is calculated as the product of number of boxes in a row multiply by the number of boxes along a column and the boxes above other i.e. the number of boxes in depth.

        Hence, the number of boxes are: 5×3×2=30 boxes.

kaheart [24]1 year ago
3 0

There are 30 boxes in the container

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Answer: Long -term capital gain

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Serena is single, so based on the Taxpayer Relief Act of 1997, she would pay no capital gains tax on the first $250,000 gain.

Therefore, $300,000 - $250,000 =  $50,000

<em>The remaining $50,000 gain is taxable because of her being single and it has been her principal residence for three years.</em>

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Air pressure may be represented as a function of height above the surface of the Earth as shown below. P(h)=PoE^-.00012h In this
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The equation to find the air pressure (P(h)) at a height above sea level (h) is given by

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1 year ago
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James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
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Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

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Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

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