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2 years ago

If a container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep, how many boxes are in the container?

Mathematics

2 answers:

aleksandrvk [35]2 years ago

8 0

<h2>Answer:</h2>

The total number of boxes that are in the container are:

30 boxes.

<h2>Step-by-step explanation:</h2>

It is given that:

A container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep.

This means that the total number of boxes is calculated as the product of number of boxes in a row multiply by the number of boxes along a column and the boxes above other i.e. the number of boxes in depth.

Hence, the number of boxes are: 5×3×2=30 boxes.

kaheart [24]2 years ago

3 0

There are 30 boxes in the container

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Cassie has 20 bracelets. How many can she give to her sister if she wants to keep 11 or more bracelets? What repeats in the poss

Mademuasel [1]

If Cassie has 20 and wants to keep 11 then we would subtract 11 from 20.

So 20 - 11 is 9.

Her sister will get 9 bracelets.

Hope this helps!

3 0

2 years ago

A 16-inch candle is lit and burns at a constant rate of 0.8 inches per hour. Let t represent the number of hours since the candl

Tamiku [17]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

The initial length of the candle is 16 inch. It also given that, it burns with a constant rate of 0.8 inch per hour.

After one hour since the candle was lit, the length of the candle will be (16 - 0.8) = 15.2 inch.

After two hour since the candle was lit, the length of the candle will be (15.2 - 0.8) = 14.4 inch. The length of the candle after two hours can also be represented by {16 - 2(0.8)}.

Hence, the length of the candle after t hours when it was lit can be represented by the function, $f(t) = 16 - 0.8t$ . $f(t) = 0$ at t = 20.

The domain of the function is 0 to 20.

The range is 0 to 16.

8 0

2 years ago

An artist cuts 4 squares with sides of length x ft from the corners of a 12 ft-by-18 ft rectangular piece of sheet metal. She be

ehidna [41]

Answer:

$V = 216x - 60x^2 + 4x^3$

Step-by-step explanation:

The volume V of the fountain is equal to:

V = L*W*h

Where L is the lenght of the fountain, W is the width of the fountain and h is the high of the fountain

We already know that h is equal to x. On the other hand, if we cut a square with side of length x, L and W are calculated as:

L = 18 - 2x

W = 12 - 2x

So, replacing L, W and h on the equation of the volume, we get:

V = (18-2x)*(12-2x)*x

Finally, simplifying the function we get:

$V = ((18*12)+(18*(-2x))+(-2x*12)+((-2x)*(-2x)))*x$

$V = (216-36x-24x+4x^2)*x\\V = (216-60x+4x^2)*x\\V = 216x - 60x^2 + 4x^3$

6 0

2 years ago

The parallel dotplots below display the girths (belly

liraira [26]

Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0

2 years ago

According to the U.S. Census Bureau (2016), a substantial pay gap still exists. The average American man, with an advanced colle

Leokris [45]

Answer:

The difference in earnings, over a 30-year career, for men vs women, is $1,200,150

Step-by-step explanation:

Per year.

The average man earns $90,761.

The average woman earns $50,756

So, per year, the difference is:

90,761 - 50,756 = 40,005

Over 30 years:

30*40,005 = 1,200,150

The difference in earnings, over a 30-year career, for men vs women, is $1,200,150

0 0

2 years ago