All categories

2 years ago

If a container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep, how many boxes are in the container?

Mathematics

2 answers:

aleksandrvk [35]2 years ago

8 0

<h2>Answer:</h2>

The total number of boxes that are in the container are:

30 boxes.

<h2>Step-by-step explanation:</h2>

It is given that:

A container has 5 rows of boxes that are stacked 3 boxes high and 2 boxes deep.

This means that the total number of boxes is calculated as the product of number of boxes in a row multiply by the number of boxes along a column and the boxes above other i.e. the number of boxes in depth.

Hence, the number of boxes are: 5×3×2=30 boxes.

kaheart [24]2 years ago

3 0

There are 30 boxes in the container

You might be interested in

Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u

Naddika [18.5K]

Answer with Step-by-step explanation:

We are given that Laplace's equation

$u_{xx}+u_{yy}=0$

We have to determine given function is solution of given laplace's equation.

If a function is solution of given Laplace's equation then it satisfy the solution.

1. $u=e^{-x}cosy-e^{-y}cosx$

Differentiate w.r.t x

Then, we get

$u_x=-e^{-x}cosy+e^{-y}sinx$

Again differentiate w.r.t x

$u_{xx}=e^{-x}cosy+e^{-y}cosx$

Now differentiate u w.r.t y

$u_y=-e^{-x}siny+e^{-y}cosx$

Again differentiate w.r.t y

$u_{yy}=-e^{-x}cosy-e^{-y}cosx$

Substitute the values in given Laplace's equation

$e^{-x}cosy+e^{-y}cosx-e^{-x}cosy-e^{-y}cosx=0$

Hence, given function is a solution of given Laplace's equation.

2. $u=sinx coshy+cosx sinhy$

Differentiate w.r.t x

$u_x=cosx coshy-sinx sinhy$

Again differentiate w.r.t x

$u_{xx}=-sin x coshy-cosxsinhy$

Now, differentiate u w.r.t y

$u_y=sinx sinhy+cosx coshy$

Again differentiate w.r.t y

$u_{yy}=sinx coshy+cosx sinhy$

Substitute the values then we get

$-sinx coshy-cosxsinhy+sinxcoshy+cosx sinhy=0$

Hence, given function is a solution of given Laplace's equation.

4 0

1 year ago

Company B loses $1575 for every employee who quits before 90 days. What is the total amount the company will lose if 2 employees

Xelga [282]

Ifgfyfufugugguihihjcjfifif

4 0

1 year ago

3. After completing a statistical analysis of a survey of 40 students, the principal

Serhud [2]

Answer:

Option A

Step-by-step explanation:

A type I error is committed when a researcher rejects the null hypothesis when it is actually true.

The null hypothesis is: U <= 50%

The alternative is: U > 50%

Thus, the principal could have committed an error by rejecting null hypothesis and concluding that more than 50% of students want earlier lunch, when in actuality 50% or less want earlier lunch.

5 0

2 years ago

When a baseball is hit by a batter, the height of the ball, h(t), at time t, t=0, is determined by the equation h(t)=-16t^2+64t+

Natali [406]

T over x is your starting debut
add 40 from your original answer and divide by two
triplemente the second number and switch your trinomial by three

6 0

2 years ago

Read 2 more answers

13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas

Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

$5+5^{2}=30$ (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

$5^{1}+5^{2}+5^{3}+...+5^{x}>19000$ (II)

Buscamos el valor de $x$ que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

$5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000$

$19530>19000$

El valor de $x$ que satisface (II) es $x=6$ .

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro $x=6$ , el número de horas que pasaron son 5 horas (1 menos que el valor de $x$ )

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0

2 years ago