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pickupchik [31]

2 years ago

10

A designer is adding a border around the edge of a rectangular swimming pool. He measures the pool and finds that the length of

the pool is 52 meters and the width is 26 meters.How long is the tile border

1 answer:

valentinak56 [21]2 years ago

5 0

The answer is 156 meters

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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable $X\sim Poisson(\lambda = 0.62)$ .

The probability function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

= 1 - P (X = 0) - P (X = 1)

$=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: $\lambda=7\times0.62=4.34$

Compute the probability of no deaths in a corps over 7 years as follows:

$P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0

2 years ago

Miguel ran for 850 meters and then walked for 2.75 kilometers.

olga55 [171]

Answer:

1900 meters

Step-by-step explanation:

He ran for 850 meters

Walked for 2.75 kilometers, and that's 2.75 * 1000 meters, which is 2750 meters

The total he walked more than he ran is 2750 - 850 = 1900 meters

4 0

2 years ago

Pooja's plant began sprouting 2days before Pooja bought it, and she had it for 98 days until it died. At its tallest, the plant

taurus [48]

Given that function H(t) models the height of Pooja's plant (in centimeters) where t is the number of days after she bought it.

Now we have to find about which number type is more appropriate for the domain of h. That means what values can be taken by the variable "t".

Since t is number of days not the hours so t will not use decimal or fraction values. It can use integer values for the number of days.

Since time is counted after she bought the plant then number of days will be positive.

Hence answer for the type of domain can be positive integers or you can say integers greater than or equal to 0.

4 0

2 years ago

Read 2 more answers

Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi

timama [110]

Answer:

(a)The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

(b)Therefore, the length of the fence is $97\frac{1}{2}$ feet$

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

$y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet$

Similarly:

$x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet$

The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

(b)Length of the Fence

The fence is rectangular shaped with:

Length = $31\frac{1}{2}$ feet$

Width = $17 \frac{1}{4}$ feet$

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

$=2(31\frac{1}{2}+17 \frac{1}{4})\\=2(31+17+\frac{1}{2}+ \frac{1}{4})\\=2(48+ \frac{3}{4})\\=96+\frac{3}{2}\\=97\frac{1}{2}$ feet$

8 0

2 years ago

Eric throws a biased coin 10 times. He gets 3 tails. Sue throw the same coin 50 times. She gets 20 tails. Aadi is going to throw

NISA [10]

Answer:

(1) Correct option (A).

(2) The probability that Aadi will get Tails is 0.40.

Step-by-step explanation:

The information provided is:

Eric throws a biased coin 10 times. He gets 3 tails.
Sue throw the same coin 50 times. She gets 20 tails.

The probability of tail in both cases is:

$P(T|E)=\frac{3}{10}=0.30$

$P(T|S)=\frac{20}{50}=0.40$

Here,

P (T|E) implies the probability of tail in case of Eric's experiment.

P (T|S) implies the probability of tail in case of Sue's experiment.

(1)

Now, it is given that Aadi is going to throw the coin once.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

In this case we need to compute the probability of Aadi getting Tails in a single toss.

As Sue uses a larger number of trials in the experiment, i.e. n = 50 > 30 times, according to the Central limit theorem, Sue's estimate is best because she throws it .

Thus, the correct option is (A).

(2)

As explained in the first part that Sue's estimate is best for getting a tail, the probability that Aadi will get Tails when he tosses the coin once is:

$P(\text{Aadi will get Tails})=P(T|A)$

$=P(T|S)\\\\=0.40$

Thus, the probability that Aadi will get Tails is 0.40.

8 0

2 years ago

Read 2 more answers