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Nataly_w [17]
2 years ago
9

For which pair of launch angles will two identical projectiles have equal ranges?. A. 19.24°, 80.54°B. 16.42°, 74.58°C. 60.23°,

29.77°D. 89.53°, 01.47°E. 42.42°, 47.59°
Physics
2 answers:
AlladinOne [14]2 years ago
4 0
The kinematic equations of motion that apply here are<span>y(t)=votsin(θ)−12gt2</span>and<span>x(t)=votcos(θ)</span>Setting y(t)=0 yields <span>0=votsin(θ)−12gt2</span>. If we solve for t, we obtain, by factoring,<span>t=<span>2vsin(θ)g</span></span>Substitute this into our equation for x(t). This yields<span>x(t)=<span><span>2v2cos(θ)sin(θ)</span>g</span></span><span>This is equal to x=<span><span>v^2sin(2θ)</span>g</span></span>Hence the angles that have identical projectiles are have the same range via substitution in the last equation is C. <span> 60.23°, 29.77° </span>
enyata [817]2 years ago
4 0

The answer is C

If you subtract the given range of a projectile from 90º, It will give you its equivalent projectile counter part in terms of Range.

So, in this example where it gives you both the projectiles and asks you which ones that have the same range, add both and if it adds up to exaclt 90º, that is your answer

60.23º + 29.77º = 90º

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Answer:

83%

Explanation:

On the surface, the weight is:

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In orbit, the weight is:

w = GMm / (R+h)²

where h is the height of the shuttle above the surface of the Earth.

The ratio is:

w/W = R² / (R+h)²

w/W = (R / (R+h))²

Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:

w/W = (6.4×10⁶ / 7.03×10⁶)²

w/W = 0.83

The shuttle in orbit retains 83% of its weight on Earth.

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2 years ago
A toroidal coil has a mean radius of 16 cm and a cross-sectional area of 0.25 cm2; it is wound uniformly with 1000 turns. A seco
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Explanation:

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B = 4π x 10⁻⁷ x (1000 / 2π x .16  )x 1 ( current = 1 A)

flux in the secondary coil

= B x area of face of coil x no of turns of secondary

= 4π x 10⁻⁷ x (1000 /2π x .16  ) .25 x 10⁻⁴ x 750

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2343.75 x 10⁻⁸

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6 0
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Complete Question:

Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth’s mass M, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.

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m = 0.001 M

For the whole process check the following page: https://www.slader.com/discussion/question/suppose-that-an-asteroid-traveling-straight-toward-the-center-of-the-earth-were-to-collide-with-our/

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If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel
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Answer:

There will be no change in the direction of the electric field .

Explanation:

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In which of the following examples does the object have both kinetic and potential energy? Select all that apply.
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Objects having both kinetic and potential energy:

water flowing downstream

a child swinging on a swing

a bouncing ball

a plane in flight at 30,000 feet

Explanation:

The kinetic energy of an object is the energy possessed by the object due to its motion. It is given by

KE=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

Therefore, an object has kinetic energy when its speed is non-zero (so, whenever it is moving).

The potential energy of an object is the energy possessed by the object due to its position in the gravitational field. It is given by

PE=mgh

where

m is the mass

g is the acceleration of gravity

h is the heigth of the object relative to the ground

Therefore, an object has potential energy whenever it is located at a certain height above the ground.

So in this problem, the objects that have both kinetic and potential energy are:

a rock at the edge of a cliff  --> NO, because the rock is at rest (so KE = 0)

water flowing downstream  --> YES, because the water is moving AND it is at a certain height above the ground

a child swinging on a swing  --> YES, because the child is moving AND it is at a certain height above the ground

a bouncing ball  --> YES, because the ball is moving AND it is at a certain height above the ground

water behind a dam  --> NO, because the water is at rest (so KE=0)

a car moving on a level road  --> NO, because the car is at ground level (so PE=0)

a plane in flight at 30,000 feet   --> YES, because the plane is moving AND it is at a certain height above the ground

a compressed spring --> NO, because the spring is at rest (so KE=0)

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

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