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Kamila [148]
2 years ago
11

Hiro wants to model the magnetic field of a bar magnet using a shoe box and pipe cleaners. He labels the ends of the shoe box N

and S.
How should he position the pipe cleaners? Check all letters that apply.

a) They should exit the box at N and enter at S.
b) They should exit the box at S and enter at N.
c) They should be put inside the box so the two ends join.
d) None should be put inside the box.
e) They should form loops outside of the box over the top, bottom, and sides of the box.
f) They should form loops outside of the box, but over only the sides of the box.
g) Mark this and return Save and Exit
Physics
2 answers:
Yuri [45]2 years ago
8 0

A) They should exit the box at N and enter at S.  

C) They should be put inside the box so the two ends join.

E) They should form loops outside of the box over the top, bottom, and sides of the box.

AlladinOne [14]2 years ago
6 0

Answer:The correct answer is (a), (c) and (e).

Explanation:

Properties of magnetic field lines.

  • They move from north to south when outside the magnet.
  • They move from south to north when inside the magnet.
  • They form closed loops with no breaks over the top, bottom and sides of the bar magnet.
  • If lines are closer to each other strength of magnetic filed will be more.
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e-lub [12.9K]

If you know the formula for horizontal range, then finding the solution is immediate:

r=\dfrac{{v_0}^2\sin2\theta}g

110\,\mathrm m=\dfrac{{v_0}^2\sin100^\circ}{9.8\,\frac{\mathrm m}{\mathrm s^2}}\implies v_0\approx33\,\dfrac{\mathrm m}{\mathrm s}

7 0
2 years ago
A circuit node has current ia entering and currents ib and ic exiting, where it is known that ia=5 ma and ib=9 ma. what is curre
Rudik [331]
The current is the flow of electrons. It is expressed as Coulombs per second, or Amperes. Since it is a flow, all that comes in must go out. The basis here is the node. Since ia is the full flow, it must be greater than ib or ic. So, I think the given information is wrong. It should be ia = 9 mA and ib=5 mA.

Current entering = Current leaving
ia = ib + ic
9 mA = 5 mA + ic
ic = 9 mA - 5 mA = 4 mA 
8 0
2 years ago
A 3.0-cm tall statue is 48 cm in front of a convex lens having a focal length of i. (2 pts) Is the image of the statue real or v
erica [24]

Explanation:

Given that,

Height of object = 3.0 cm

Distance of object u= 48 cm

Focal length = 48 cm

We need to calculate the image distance

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{20}=\dfrac{1}{v}+\dfrac{1}{-48}

\dfrac{1}{v}=\dfrac{1}{20}+\dfrac{1}{48}

\dfrac{1}{v}=\dfrac{17}{240}

v=14.11\ cm

(I). The image is real.

(II).  The distance of the image from the lens is 14.11 cm.

(II). The image is inverted.

(IV). We need to calculate the height of the image

Using formula of magnification

m = \dfrac{v}{u}=\dfrac{h'}{h}

\dfrac{v}{u}=\dfrac{h'}{h}

Put the value into the formula

\dfrac{14.11}{48}=dfrac{h'}{3.0}

h'=\dfrac{14.11}{48}\times3.0

h'=0.88\ cm

The height of the image is 0.88 cm.

Hence, This is the required solution.

6 0
2 years ago
The nucleus of an atom consists of protons and neutrons (no electrons). A nucleus of a carbon‑12 isotope contains six protons an
andriy [413]

Answer:

7 electrons

Explanation:

We can solve the problem by using the law of conservation of electric charge: in fact, the total electric charge before and after the collision must be conserved.

Before the collision, we have:

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- A nucleus of nitrogen-14, consisting of 7 protons (charge +1 each) + 7 neutrons (charge 0 each), so total charge of +7

So the total charge before the collision is +6+7=+13 (1)

After the collision, we have:

- 17 protons (charge +1 each): total charge of +17

- 4 antiprotons (charge -1 each): total charge of -4

- 7 positrons (charge +1 each): total charge of +7

- 25 neutral particles (charge 0 each): total charge of 0

- N electrons (charge -1 each): total charge of -N

So the total charge after the collision is +17-4+7+0-N=+20-N (2)

Since the charge must be conserved, we have (1) = (2):

+13 = +20 - N

Solving for N,

N = 20 - 13 = 7

So, there are 7 electrons.

4 0
2 years ago
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Fantom [35]
We want to know the amount of force that stretches the spring 0.22 m.
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The weight of the mass is (mass) times (gravity).
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gravity has different values on every planet.  I shall assume that
this whole springy question is taking place on Earth, so that the
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The weight of the mass is (0.4 kg) x (9.8 m/s²) = 3.92 Newtons.

The spring constant is

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= (3.92 Newtons) / (0.22 meters)

= (3.92 / 0.22) Newtons/meter

= 17.82 N/m .

8 0
2 years ago
Read 2 more answers
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