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Alex777 [14]
2 years ago
6

A circuit node has current ia entering and currents ib and ic exiting, where it is known that ia=5 ma and ib=9 ma. what is curre

nt ic?
Physics
1 answer:
Rudik [331]2 years ago
8 0
The current is the flow of electrons. It is expressed as Coulombs per second, or Amperes. Since it is a flow, all that comes in must go out. The basis here is the node. Since ia is the full flow, it must be greater than ib or ic. So, I think the given information is wrong. It should be ia = 9 mA and ib=5 mA.

Current entering = Current leaving
ia = ib + ic
9 mA = 5 mA + ic
ic = 9 mA - 5 mA = 4 mA 
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A single slit, which is 0.050 mm wide, is illuminated by light of 550 nm wavelength. What is the angular separation between the
likoan [24]

Answer:

The separation between the first two minima on either side is 0.63 degrees.

Explanation:

A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:

a\sin \theta_n=n\lambda

with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:

for the first minimum

a\sin \theta_1=(1)\lambda

solving for θ1:

\theta_1=\arcsin (\frac{\lambda}{a})=\arcsin (\frac{550\times10^{-9}}{0.05\times10^{-3}})

\theta_1=0.63 degrees

for the second minimum:

a\sin \theta_2=(2)\lambda

\theta_2=\arcsin (\frac{2\lambda}{a})=\arcsin (\frac{2*550\times10^{-9}}{0.05\times10^{-3}})

\theta_2=1.26 degrees

So, the angular separation between them is the rest:

\Delta \theta =1.26-0.63

\Delta \theta=0.63

4 0
2 years ago
A valuable statuette from a Greek shipwreck lies at the bottom of the Mediterranean Sea. The statuette has a mass of 10,566 g an
leonid [27]

Answer:

A) W = 103.55 N

B) mass of displaced water = 4186 g

C) W_displaced water = 41.06 N

D) Buoyant force = 41.06 N.

E) ZERO

F) 62.54 N

Explanation:

We are given;

mass of statuette;m = 10,566 g = 10.566 kg

volume = 4,064 cm³

Density of seawater;ρ = 1.03 g/mL = 1.03 g/cm³

A) The dry weight of the statuette can be calculated as;

W = mg

So;

W = 10.556 × 9.81

W = 103.55 N

B) Mass of displaced water is calculated from;

Density = mass/volume

So, mass = Density × Volume

m = 1.03 × 4,064 = 4186 g

C) Weight of displaced water is given by;

W_displaced water = (m_displaced water) × g

W_displaced water = 4.186 kg × 9.81 m/s^2 = 41.06 N

D) The buoyant force is the same as the weight of the displaced water.

Thus, Buoyant force = 41.06 N.

E) The apparent weight of the statuette is calculated from;

Apparent weight = Dry weight - Weight of displaced water

Apparent weight = 103.6 N - 41.06 N = 62.54 N. It is sitting on the bottom of the sea, so the sea floor is providing an opposite force that is equal but opposite the weight so that the net force on the statuette is zero. Since It has zero acceleration, in any direction, hence the net force on it is zero.

F. From E above, The Force required to lift the statuette = 62.54 N

4 0
2 years ago
A soccer ball player bounces the ball off her head, changing the velocity of the ball. She changes the x-component of the veloci
Nadya [2.5K]

The change in horizontal velocity is (4.7 - 8.1) = -3.4 m/s

The change in vertical velocity is (3.2 + 3.3) = 6.5 m/s

These are the components of velocity DELIVERED to the ball by the player's pretty head during the collision.  

The magnitude of the change in velocity is √(-3.4² + 6.5²) = 7.336 m/s .

The magnitude of the ball's change in momentum is (m · v) = (0.44 · 7.336) = 3.228  kg-m/s .

==> The change in the ball's momentum is exactly the <em>impulse</em> during the collision. . . . . . <em>3.228 kg-m/s</em> .

==> The direction of the impulse is the direction of the change in momentum:  (-3.4)i + (6.5)j

The direction is  arctan (6.5 / -3.4)  =  -62.39°

That's clockwise from the +x axis, which is roughly "southeast".  The question wants it counterclockwise from the +x axis.  That's (360-62.39) =

<em>Direction of the impulse = 297.61°</em>

<em></em>

We know that impulse is equivalent to the <u>change in momentum</u>, and that's how I approached the solution.  Impulse is also (<u>force x time</u>) during the collision.  We're given the time in contact, but I didn't need to use it.  I guess I would have needed to use it if we were interested in the FORCE she exerted on the ball with her head, but we didn't need to find that.

5 0
2 years ago
How far must 5N force pull a 50g toy car if 30J of energy are transferred?​
Alborosie

Answer: 6 m

Explanation:

30 = 5 * d

d = 30/5

d = 6 m

7 0
2 years ago
The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t
marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

I = 9.7 \times 10^{37} kg m^2

Explanation:

Since Earth is considered as solid sphere

So we will have

I = \frac{2}{5}M_eR_e^2

so we will have

I = \frac{2}{5}(5.97 \times 10^{24})(6.371 \times 10^6)^2

so we have

I = 9.7 \times 10^{37} kg m^2

3 0
2 years ago
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