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Nadya [2.5K]
2 years ago
9

1. There are 25 students who started computer programming in elementary school and 25 students who started computer programming

in middle school. The first group had a mean final project grade of 95% and the second group had a mean final project grade of 92%.
The line plot shows the differences after 10 rerandomizations. Determine whether the difference in the means of the two groups is significant based on the line plot. Explain your answer.

Mathematics
1 answer:
guapka [62]2 years ago
4 0

the answer is attached below

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I did the assignment and got it correct

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Determine the solution set of x^2-80=0.
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X^2 - 80 = 0
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mrs bean bought a business at the start of 2006 the business was then valued £30000 Since Mrs Beans takeover, the business gas c
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3 Explain how the distributive property helps us multiply the following polynomials and why and how the final products differ: ●
Pavel [41]
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Over the past decade, the mean number of hacking attacks experienced by members of the Information Systems Security Association
fredd [130]

Answer:

P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)

And we can find this probability using the complement rule and the normal standard distribution and we got:

P(z>6.302)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of attacks of a population, and for this case we know the distribution for X is given by:

X \sim N(510,14.28)  

Where \mu=510 and \sigma=14.28

We are interested on this probability

P(X>600)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>600)=P(\frac{X-\mu}{\sigma}>\frac{600-\mu}{\sigma})=P(Z>\frac{600-510}{14.28})=P(z>6.302)

And we can find this probability using the complement rule and the normal standard distribution and we got:

P(z>6.302)=1-P(z

7 0
2 years ago
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