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fiasKO [112]
2 years ago
8

Which option describes wearable technology? A. the incorporation of technology into objects we use regularly B. rugged technolog

y that can withstand the elements without much damage C. computing systems that derive energy from the user's biological processes D. mobile technology that is extremely portable E. extremely small and powerful computing systems
Computers and Technology
1 answer:
vichka [17]2 years ago
8 0

The correct answer is

A.  the incorporation of technology into objects we use regularly

#Platogang

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Menus are attached to windows by calling the _____ method.
Kruka [31]

Answer: setJMenubar

Explanation:Menus that are component of the Menu bar that display the options and tools for any function that can be performed in the system have the connection with the window in the field of java through the command of the setJMenubar. It is the command which is given to execute to bring the menu to the particular frame and get it attached according to the JFrame. Therefore, the correct option is setJMenubar.

6 0
2 years ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
Write a public static method named printArray, that takes two arguments. The first argument is an Array of int and the second ar
Serjik [45]

Answer:

Written in Java

public static void printArray(int myarr[], String s){

       for(int i = 0; i<myarr.length;i++){

           System.out.print(myarr[i]+s);

       }

   }

Explanation:

This defines the static method alongside the array and the string variable

public static void printArray(int myarr[], String s){

The following iteration iterates through the elements of the array

       for(int i = 0; i<myarr.length;i++){

This line prints each element of the array followed by the string literal

           System.out.print(myarr[i]+s);

       }

   }

The method can be called from main using:

<em>printArray(myarr,s);</em>

Where myarr and s are local variables of the main

5 0
2 years ago
In this programming assignment, you will create a hierarchy of classes (see below) that inherit from the beverage class. The bas
harina [27]

Answer:

public class GetInfo{

Beverage[]  beverages=new Beverage[100];

int i=0;

GetInfo(Beverage b){

beverages[i]=b;

i++;

}

public void Display(){

for(int i=0;i<beverages.length;i++)

cout<<beverage[i].tostring();

}

Explanation:

we are taking Beverages array to store all values and in constructor we are adding that to the list and Display() function prints the vale

5 0
2 years ago
Float_abs - return bit-level equivalent of absolute value of f for * floating point argument f. * both the argument and result a
olga_2 [115]

#include <stdio.h>

int main(void) {

            // your code goes here

            //unsigned a =float_times_four(0x80000000);

            unsigned float_times_four(unsigned uf){

                unsigned expn = (uf >> 23) & 0xFF;

                printf(expn);

                unsigned sign = uf & 0x80000000;

                unsigned frac = uf & 0x007FFFFF;

                if(expn == 255 ||(expn == 0 && frac ==0))

                    return uf;

                if(expn){

                    expn<<2;

                }else if(frac == 0x007FFFFF){

//here 0x7FFFFF given by you that is wrong you place this 0x007FFFFF will excute

                    frac>>2;

                    expn<<2;

                }else{

                    frac<<=2;

                }

return (sign) | (expn <<23) | (frac);

            }

            return 0;

}

3 0
2 years ago
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