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Alex Ar [27]
2 years ago
9

Davis has 141 figures in his action figure collection. One-third of the figures are sports related. How many of the figures in D

avis’ collection are NOT sports related
Mathematics
1 answer:
Lelu [443]2 years ago
7 0

We have been given that Davis has 141 figures in his action figure collection. One-third of the figures are sports related.

To find the number of figures that are not sports related we will find 2/3 of 141 as 2/3 of the figures will be not related to sports.

\text{ Figures not related to sports}=141\times\frac{2}{3}

\text{ Figures not related to sports}=47\times2

\text{ Figures not related to sports}=94

Therefore, 94 figures in Davis’ collection are not sports related.

 

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$218,475

Step-by-step explanation:

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2 years ago
Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th
larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

p_v =2*P(z>0.546)=0.585  

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

\hat p=0.2 estimated proportion  

p_o=0.16 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:  

Null hypothesis:p=0.16  

Alternative hypothesis:p \neq 0.16  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>0.546)=0.585  

4 0
2 years ago
The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,
dmitriy555 [2]

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

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#We first calculate the probability of a camera having a lens defect;

P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025

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P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125

The  the probability that a camera has a lens defect given that it has a charging defect is calculated as:

P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025

Hence,  the probability that a camera has a lens defect given that it has a charging defect is 0.025

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Answer:

The answer is 24.

Step-by-step explanation:

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Answer:

Erin gets a result number of 5

Step-by-step explanation:

Assuming this is a 'word problem.' -- These are small numbers so you could use your hand for visual. :)

Start with 4 fingers up. (adding a negative to a positive is basically subtraction sooo...) put 3 fingers down. You now have one finger up. (subtracting a negative is just addition, think about taking those two minus signs and putting them together to get an addition sign.) now add 4 fingers to your one finger. You should be left with 5 fingers up!

Hope I helped. Hang in there, it will get easier!

8 0
2 years ago
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