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SpyIntel [72]
2 years ago
14

Scrie numerele 840 4220 2840 ca produse de doi factori dintre care unul sa fie scris cu o cifra

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

 

840 = 1×840=2×420 = 3×280 = 4×210 = 5×168 = 6×140 = 7×120 = 8×105

4220=1×4220 = 2×2110 = 4×1055 = 5×844

2840 = 1×2840 = 2×1420 = 4 × 710 = 5 × 568 = 8 × 355




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Semmy [17]

Answer:

Answer you chosen in the option is correct!

Step-by-step explanation:

Here we can see that Remmi got x =3y -2

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therefore equation becomes  as third option so answer chosen by you is correct

8 0
2 years ago
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Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?
sveta [45]

Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

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Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

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<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

6 0
2 years ago
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Answer:

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2 years ago
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7 0
2 years ago
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Step-by-step explanation:

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