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ArbitrLikvidat [17]
1 year ago
13

(01.07 MC) Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points and E. The

y are also intersected by transversal EC. Angle ABC measures 70 degrees. Angle CED measures 30 degrees. Given: line BC is parallel to line ED m∠ABC = 70° m∠CED = 30° Prove: m∠BEC = 40° Statement Justification line BC is parallel to line ED Given m∠ABC = 70° Given m∠CED = 30° Given m∠BEC + m∠CED = m∠BED Angle Addition Postulate m∠BEC + 30° = 70° Substitution Property of Equality m∠BEC = 40° Subtraction Property of Equality Which of the following accurately completes the missing statement and justification of the two-column proof? m∠ABC = m∠CED; Corresponding Angles Theorem m∠ABC = m∠CED; Alternate Interior Angles Theorem m∠ABC = m∠BED; Corresponding Angles Theorem m∠ABC = m∠BED; Alternate Interior Angles Theorem

Mathematics
2 answers:
Brrunno [24]1 year ago
6 0

Answer:

m∠ABC = m∠BED; Corresponding Angles Theorem

Step-by-step explanation:

<u>Given:</u> line BC is parallel to line ED m∠ABC = 70° m∠CED = 30°

<u>Prove:</u> m∠BEC = 40°

Statement Justification

1. line BC is parallel to line ED - Given

2. m∠ABC = 70° - Given

3. m∠CED = 30° - Given

4. m∠BEC + m∠CED = m∠BED - Angle Addition Postulate

5. m∠ABC = m∠BED - Corresponding Angles Theorem

6. m∠BEC + 30° = 70° - Substitution Property of Equality

7. m∠BEC = 40° Subtraction Property of Equality

Len [333]1 year ago
5 0

Answer:

m∠ABC = m∠BED - Corresponding Angles Theorem

Step-by-step explanation:

I took the test and got it right

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4 0
1 year ago
The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation y = −0.4x2 + 3x, where y is the he
Tamiku [17]

Answer:

5 feet

Step-by-step explanation:

The path traveled by a bottlenose dolphin as it jumps out of water is modeled by the equation,

y=-0.4x^2+3x

where y is the height above water and x is the horizontal distance in feet.

If a beam of light is shone upward at an angle modeled by the equation

x+y=10

A beam of light hit the dolphin.

So, line must be intersect path of dolphin.

Using substation method,

Substitute y=10-x into dolphin equation.

10-x=-0.4x^2+3x

-0.4x^2+4x-10=0

x=\dfrac{-4\pm\sqrt{4^2-4(-10)(-0.4)}}{2(-0.4)}

x=5\text{ feet }

y=5\text{ feet }

Hence, The beam hit dolphin at 5 feet.

8 0
2 years ago
Six pipes are laid end to form a row.each pipe is 9 1/3 inches long.how long is the row of pipes in feet?
laiz [17]

six pipes are laid end to end to form a row. Each pipe is 9 1/3 inches long. how long is the row of pipes, in feet?

Answer:

4.67 feet or 4 feet 8 inches or 4\frac{2}{3}feet

Step-by-step explanation:

Let x be the length of the row pipes.

Given:

Number of pipes = 6

Each pipe has length 9\frac{1}{3} inches. and six pipes are laid end to end to form a row.

The total length of the row is equal to length of the 6 pipes.

So, total length of row = Number of pipes \times Length of the pipe

x=\frac{28}{3}\times 6

x=28\times 2

x=56 inches

convert inch into feet.

x=\frac{56}{12}

x=4.67 feet

Therefore, The length of the row is 4.67 feet or 4 feet 8 inches or 4\frac{2}{3}feet .

3 0
2 years ago
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
1 year ago
A and B will take the same 10-question examination. Each question will be answered correctly by A with probability .7, independe
MatroZZZ [7]

Answer:

a) The expected number of questions that are answered correctly by both A and B = 11 (7 + 4).

b) The Variance of the number of questions that are answered correctly by either A or B = 2.25.

Step-by-step explanation:

Number of questions in the examination = 10

Probability of A's answer being correct = 0.7

Probability of B's answer being correct = 0.4

The expected number of questions that are answered correctly by both A and B:

           Probability of       Expected        

        Correct Answer       Value          Variance

A              0.7                     7 (0.7 * 10)    2.25

B              0.4                     4 (0.4 * 10)    2.25

Total expected value =    11

           Mean =                  5.5                2.25

5 0
1 year ago
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