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ivanzaharov [21]
2 years ago
6

What is the geometric mean of 3 and 147

Mathematics
1 answer:
Makovka662 [10]2 years ago
3 0

multiply the two numbers together, then take the square root

3* 147

441

sqrt(441)

21

The geometric mean is 21

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Andrew has a fish tank in the shape of a rectangular prism, and he needs to know the volume of water necessary to fill the tank.
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Answer:

The correct option is D.

Step-by-step explanation:

Domain is the set of all posible

The volume of a rectangular prism is

V=\text{Base area}\times height

where,

\text{Base area}=length\times width

Dimensions can not be negative. So, the width and volume are always positive.

From the graph it is noticed that

In interval (-\infty, -5), width and volume is negative, so (-\infty, -5) interval is not the domain.

In interval (-5,0), width is negative, so (-5,0) interval is not the domain.

In interval (0,3), volume is negative, so (0,3) interval is not the domain.

In interval (3,\infty), width and volume is negative, so (3,\infty) interval is not the domain.

Therefore the correct option is D.

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The answer is 40 by 48 inches

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Find the volume of the right rectangular prism whose side lengths are 5 cm, 3 cm, and 13 cm
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I hope this helps you




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A certain reaction is endothermic in the forward direction. The reaction has less moles of gas on the product side. Which of the
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decreasing the pressure

Step-by-step explanation:

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An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They
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Answer:

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =2.0233 represent the sample mean 1  

\bar X_2 =3.048 represent the sample mean 2  

n1=15 represent the sample 1 size  

n2=15 represent the sample 2 size  

s_1 =4.893387 population sample deviation for sample 1  

s_2 =5.12399 population sample deviation for sample 2  

\mu_1 -\mu_2 parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: \mu_1 = \mu_2

H1: \mu_1 \neq \mu_2

And we can do this using the confidence interval for the difference of means.

Solution to the problem  

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 15+15-2=28  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that t_{\alpha/2}=\pm 1.701  

Now we have everything in order to replace into formula (1):  

-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137  

-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087  

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0
2 years ago
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