Question

A diver is on the 10m platform, preparing to perform a dive. the diver's height above the water, in metres, at time t can be modelled using the equation : h(t)= -4.9(t)^2 + 2t + 10.. Estimate the rate at which the diver's height above the water is changing as the diver enters the water. be sure to include at least 3 intervals from booth sides in your table. I think its instantaneous rate of change..

Answer 1

We are given with 2 which means the initial velocity is 2 m/s and the height is 10 m initially. we are given the expression h(t)= -4.9(t)^2 + 2t + 10. we can also use 2ay = Vf2 - Vo2 
for three intervals: 
2*9.8*7 = Vf2 - 10^2; Vf is 15.40 m/s
2*9.8*8 = Vf2 - 10^2; Vf is 16.02 m/s
2*9.8*9 = Vf2 - 10^2; Vf is 16.63 m/s