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2 years ago

PLEASE HELP WILL MAKE BRAINLIEST!!! Factor using the identity:

Mathematics

2 answers:

larisa86 [58]2 years ago

8 0

Answer:

(2 z + 3) (4 z^2 - 6 z + 9)

Otrada [13]2 years ago

4 0

Answer:

(2 z + 3) (4 z^2 - 6 z + 9)

Step-by-step explanation:

8z3 + 27

a = 2z

b = 3

a^2 = (2z)^2 = 2z^2

ab = (2z)*3 =6z

b^2 = 3^2 =9

a3 + b3 = (a + b)(a2 – ab + b2)

8z^2 +27 = (2z+3) (4z^2 -6z +9)

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You are hiking and trying to determine how far away the nearest cabin is, which happens to be due north from your current positi

Damm [24]

Answer:

Cabin is 567 yards away...

Step-by-step explanation:

The angle 21.2° is also the angle of the upper interior angle of the triangle (near the cabin)

Use the tan function:

opposite = 220 yards

adjacent = x

tan(21.2°) = (opposite / adjacent)

tan(21.2°) = 220 yards/x

x * tan(21.2°) = 220 yards

x = 220 yards/ tan(21.2°)

x= 220/ 0.388

x = 567 yards.

Cabin is 567 yards away...

6 0

2 years ago

If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50

Fed [463]

Lets use the formula $RWT=J$ to solve this, where,

R is the rate
W is the number of workers/things
T is time
J is number of jobs/things

"If it takes 10 seconds for 10 printers to print out 10 pages of paper" - here -

W is 10 printers, T is 10 seconds, and J is 10 pages. We can write:

$R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1$

"how many seconds will it take 50 printers to print out 50 pages of paper" - here we use $R=0.1$ (previously found) to figure out T.

$RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10$

So it will take 10 seconds for 50 printers to print 50 pages.

ANSWER: 10 seconds

4 0

2 years ago

Read 2 more answers

Agent Hunt is transferring classified files from the CIA mainframe to his flash drive. The variable S models the size of the fil

amid [387]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1:}\\\\\text{Calculate the value of }S\ \text{in}\ 10s,\ 20s,\ 30s,\ ... \text{and difference if them}\\\\for\ t=10:\\\\S=5(10)+45=50+45=95\\\\for\ t=20:\\\\S=5(20)+45=100+45=145\\\\for\ t=30:\\\\S=5(30)+45=150+45=195\\\\195-145=50\\145-95=50\\\\\boxed{50\ MB\ per\ 10s}$

$\bold{METHOD\ 2:}\\\\S_1=5t+45\to \text{in t second}\\\\S_2=5(t+10)+45\to \text{10 second leter}\\\\\text{Difference}\\\\S_2-S_1=5(t+10)+45-(5t+45)=5t+50+45-5t-45=50\\\\\boxed{50MB\ per\ 10s}$