Your question asks for an expression, so you would expect an answer in the form of an equation containing variables. This is because you have only 2 independent equations with 3 unknowns. That makes the system unsolvable.
Suppose v₁ is the mountaineer's velocity during the 1,000-foot trail. Then, v₂ is his speed for the 5,000-foot trail. The equation relating these two variables is:
v₂ = 2v₁ - 10 ---> equation 1
Then, you find the equation for the total number of hours he climbed. That would be the distance divided by their respective speed.
t = 1000/v₁ + 5000/v₂ ----> equation 2
Substituting equation 1 to equation 2,
t = 1000/v₁ + 5000/(2v₁ - 10)
t = 1000/v₁ + 5000/2(v₁-5)
t = 1,000/v₁ + 2,500/(v₁-5)
Answer:
Lixin obtains 15 marks
Step-by-step explanation:
Lets write two equations based on the question where: <u>D= Devi and L=Lixin</u>
D=L+15 <em>- "devi scores 15 marks more than lixin"</em>
D=2L <em>- "devi obtains twice as many marks as lexin"</em>
Now, substitute 2L as D in the first equation we wrote: (D=L+15)
2L=L+15
Next, subtract L from both sides:
<u>L=15</u>
Alright, lets get started.
At the beginning of her training, she is able to run 2 miles without stopping means 2 will be in the addition when we will write the equation for her running miles.
Her goal is to increase her distance by three quarters of a mile each week.
Means in first week, she will add the distance = 
miles
Suppose she runs x weeks, so shee will add distance = 
So, suppose she runs total number of miles = d, then
Where d is total numer of miles she runs
x is number of weeks : Answer
Hope it will help :)
Answer:
Step-by-step explanation:
Total weight of all of the filled jars with jam = 211.2 ounces
When empty, each jar weighs 1.2 ounces
Total weight of 2 dozens of empty jar = 24 × 1.2 ounces
= 28.8 ounces
Total weight of jam in 2 dozens jar = Total weight of all of the filled jars with jam - Total weight of 2 dozens of empty jar
= 211.2 ounces - 28.8 ounces
= 182.4 ounces
The weight of jam in one jar = 182.4 ounces / 24 jars
= 7.6 ounces
The weight of jam in one jar = 7.6 ounces
Answer:
B. first step
6/7x=7/8-1/2
c. second step
6/7x=7/8-4/8=3/8
d. and e are the same
x=3/8x7/6
Step-by-step explanation:
