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2 years ago

The sum of eight times a number and negative four exceeds twelve.

Mathematics

2 answers:

Ganezh [65]2 years ago

5 0

Answer: Our required inequality would be

$(8x-4)>12$

Step-by-step explanation:

Let the number be 'x'.

Eight times a number is expressed as

$8x$

Sum of eight times a number and negative four is expressed as

$8x-4$

the above exceeds twelve is expressed as

$(8x-4)>12$

Hence, our required inequality would be

$(8x-4)>12$

Aliun [14]2 years ago

3 0

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Answer:

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For Question b

$2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}$

Given that x = 4, y = 3, and dx/dt = -5.

$\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\ \\\frac{dx}{dt}=3\frac{3}{4}$

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