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Eduardwww [97]
2 years ago
14

Rachel paints 5 1 2 512 square meters of wall space in 1 3 13 hour. What area of wall space can she paint in 1 hour? One 200-gra

m bag of rice costs $8.12. How much does 1 kilogram of rice cost? (Note that 1000 g = 1 kg.) John ran 1 2 12 mile in 5 minutes, and Al ran 1 3 13 mile in 4 minutes. Which runner ran at a faster rate? At a certain store, a half-gallon jug of milk costs $2.95, and a gallon jug of milk costs $5.95. Which milk has a cheaper price: the half-gallon or gallon jug? A package of nine 12-ounce cans of cola costs $7.50. A half-gallon bottle of the same cola is sold for $2.90. Which cola has a cheaper price, the cans or the bottle?
Mathematics
1 answer:
Advocard [28]2 years ago
3 0

QUESTION 1

It was given that Rachel can paint 512 square meters of wall in 13 hours.


We can write the ratio,

512\:m^2:13\:h.

We want to find what area of wall space she can paint in 1 hour.

Let the area of wall space she can paint in 1 hour be x square meters.


We  can again write the ratio,


x\:m^2:1\:h.

We know this is going to be less, so if less more divides.


x=\frac{1\times 512}{13} m^2

This gives,

x\approx 39.38m^2 to the nearest hundredth.


QUESTION 2

It was given that;

200g:8.12\:dollars.

We want to find how much one kilogram of rice costs and we also know that,

1kg=1000g.


so we let x be the cost of 1 kg.


Then,

1000g:x\:dollars.


We know this is going to be more,so if more less divides,

x=\frac{8.12\times 1000}{200}\:dollars


x=40.6\:dollars


Therefore 1k cost $ 40.60


QUESTION 3

We were given that, John ran 12 miles in 5 minutes.

We can write this ratio as

12:5

or

\frac{12}{5}

Al ran 13 miles in  4 minutes.


We can write this one too as,

13:4 or

\frac{13}{4}


The least common denominator for the two fractions is 20.


In equivalent fractions, John 's rate is

\frac{12}{5}=\frac{48}{20}


and

Al's rate is

\frac{13}{4}=\frac{65}{20}


We can see that, in 20 minutes, John covers 48 miles while Al covers 65 miles.

Hence, Al ran at a faster rate.

QUESTION 4


We were given that, a half-gallon jug of milk costs $ 2.95 at a certain store.

We can write this as a ratio to get,

\frac{1}{2}\:jug:2.95\:gallon.

When we multiply each term of the ratio by 2, we get,

1\:jug:5.90\:gallon.

This means that 1 jug of milk costs $ 5.90 at this same store.


We were given that at another store, a gallon jug of milk costs $ 5.95.

Therefore the half gallon jug of milk for $ 2.95  is cheaper.


QUESTION 5

We were given that at a certain store, a package of nine 12-ounce cans of cola costs $7.50

Nine 12 ounce cans corresponds 108 ounces in total.


If 108 ounces corresponds to $ 7.50, then,

64 ounces corresponds to \frac{64\times 7.50}{108}=4.44 \:dollars.

This means that a half-gallon cola in this store costs approximately $ 4.44.


If a half- gallon bottle of the same cola is sold for 2.90 dollars at a different store, this one is cheaper.

Hence the bottle is cheaper.




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The perimeter of the original rectangle is:
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 The area of the original rectangle is:
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the new area and the new perimeter are:
 
P '= 140
 
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Answer:

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p(k) =  \frac{1}{3}

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P(a) =  \frac{1}{3}

Step-by-step explanation:

Generally when two fair 6-sided dice is rolled the doubles are

(1 1) , ( 2 2) , (3 3) , (4 4) , ( 5 5 ), (6 6)

The total outcome of doubles is N = 6

The total outcome of the rolling the two fair 6-sided dice is

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Generally the probability that doubles (i.e., having an equal number on the two dice) were rolled is mathematically evaluated as

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Looking at this outcome we see that there are two doubles present

So

The conditional probability that doubles were rolled is mathematically represented as

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p(k) =  \frac{1}{3}

Generally when two fair 6-sided dice is rolled the number of outcomes that would land on different numbers is L = 30

And the number of outcomes that at least one die is a 1 is W = 10

So

The conditional probability that at least one die is a 1 is mathematically represented as

P(a) =  \frac{W}{L}

=> P(a) =  \frac{10}{30}

=> P(a) =  \frac{1}{3}

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