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Dmitry_Shevchenko [17]

2 years ago

5

5 markers cost $6.55. Which equation would help determine the cost of 44 markers?

1 answer:

Studentka2010 [4]2 years ago

4 0

Question

5 markers cost $6.55. Which equation would help determine the cost of 44 markers?

Answer:

<h2>5 : 6.55 = 44 : x</h2>

Step-by-step explanation:

5 : 6.55 = 44 : x

x = 6.55 * 44 : 5

x = 57.64

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The perimeter of a pool table is about 7.8m. four times the length equals nine times the width. What are the dimensions of the t

Nana76 [90]

The pool's dimension are l = 2.7 m and w = 1.2 m

Step-by-step explanation:

Step 1 :

Given

The pool's perimeter = 7.8 m

Four times the pool's length = nine times the pool's width.

=> 4l = 9w => l = ( $\frac{9}{4}$ ) w

Where l is the pool's length and w is the pool's width

Step 2:

The rectangle's formula for perimeter is 2 (l+w)

Substituting l = ( $\frac{9}{4}$ ) w ,

2[ ( $\frac{9}{4}$ ) w + w] = 7.8 (given)

( $\frac{13}{2}$ ) w = 7.8 = > w = 1.2 m

Step 3 :

l = ( $\frac{9}{4}$ ) w = ( $\frac{9}{4}$ ) 1.2 = 2.7

l = 2.7 m

Step 4 :

Answer :

The pool's dimension are l = 2.7 m and w = 1.2 m

6 0

2 years ago

Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit

Effectus [21]

Work the information to set inequalities that represent each condition or restriction.

2) Name the variables.

c: number of color copies
b: number of black-and-white copies

3) Model each restriction:

i) <span>It takes 3 minutes to print a color copy and 1 minute to print a black-and-white copy.
</span><span>
</span><span>3c + b
</span><span>
</span><span>
</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
</span><span>
</span><span>
</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

3c + b ≤ 12
<span />

4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

iv) The final region is the intersection of the above mentioned shaded regions.

v) You can see such graph in the attached figure.

6 0

2 years ago

Danica is in the observation area of the sears tower in chicago overlooking lake michigan. She sights two sailboats going due ea

inessss [21]

Answer:

The boats are far apart by 4506.1 feet

Step-by-step explanation:

from the graph attached

i) BC = 1353 $\times tan(71\textdegree)$ = 2761.82 feet

ii) BD = 1353 $\times tan(58\textdegree)$ = 1744.28 feet

iii) the boats are far apart by = CD = CB + BD = 2761.82 + 1744.28 = 4506.1 feet

3 0

2 years ago

Members of a junior high basketball team want to brag about how tall they are. First, they measured each player’s height in inch

enyata [817]

First to find the median we need to put the numbers in order from least to greatest.

62, 64, 65, 66, 67, 69, 83

Now take a number from each side

64, 65, 66, 67, 69

Once again.

65, 66, 67

On last time

66

So the median is 66.

Now to find the mean we must add all the numbers up

64+67+83+65+66+62+69

which equals 476

Now divide 476 by the total number of heights which is 7

476/7=68

So the mean is 68

Answers: Mean; 68 Median; 66

3 0

2 years ago

Read 2 more answers

While driving home for the holidays, you can’t seem to get Little’s Law out of your mind. You note that your average speed of tr

suter [353]

Answer:

1,200 cars per hour

Step-by-step explanation:

Let's suppose the car flow is constant and based on the observations stated in the problem.

If we set and imaginary car counter where your car is, then there are 25 cars in ¼ of a mile (including yours) going at your same speed.

Now compute how long it will take to travel ¼ mile. As your speed is constant 60 mph, we can cross multiply

60 miles -----------> 1 hour

¼ of a mile --------> x hours

and

60/ (¼) = 1/x ---------> x = 1/240 hours.

This means that in 1/240 hours the 25 cars will be passing the counter.

Now compute how many cars will pass through our counter in 1 hour. Again, cross multiplying

1/240 hours -------> 25 cars

1 hour --------------> x cars

and

1/240 = 25/x -------> x = 25*240 = 1,200 cars.

So, the flow rate of the highway (going in your direction) in cars per hour is 1,200 cars per hour.

7 0

2 years ago