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tekilochka [14]
2 years ago
10

3(5z-7)+2(9z-11)=4(8z-7)-111

Mathematics
2 answers:
NISA [10]2 years ago
5 0
3(5z - 7) + 2(9z - 11) = 4(8z - 7) - 111
15z - 21 + 18z - 22 = 32z - 28 - 111
33z - 43 = 32z - 139
33z - 32z = -139 + 43
z = - 96
nika2105 [10]2 years ago
3 0
Hey there, Lets solve this together. 

3(5z - 7) + 2(9z - 11) = 4(8z - 7) - 111

15z - 21 + 18z - 22 = 32z - 28 - 111

33z - 43 = 32z - 139

33z - 32z = -139 + 43

z = - 96

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In the figure, ABC DFE. What is the perimeter of ABC in inches?
lys-0071 [83]

Answer:

Step-by-step explanation: 54in

7 0
2 years ago
Judy’s measured potassium level varies according to the Normal distribution with μ = 3.8 and σ = 0.2 mmol/l. Let us consider wha
Basile [38]

Answer:

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 3.8, \sigma = 0.2, n = 4, s = \frac{0.2}{\sqrt{4}} = 0.1

What is the blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L?

This is the value of X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.645 = \frac{X - 3.8}{0.1}

X - 3.8 = -1.645*0.1

X = 3.64

The blood potassium level L such that the probability is only 0.05 that the average of four measurements is less than L is 3.64.

8 0
2 years ago
Read 2 more answers
Question 1: Classify the system of equations and identify the number of solutions. 3 = 4x + y 2y = 6 − 8x Answers: inconsistent;
Mariana [72]

Answer:

1st: consistent and dependent

2nd: (-2,0). Simply put the called and check.

7 0
2 years ago
In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?
PilotLPTM [1.2K]

Answer:

Therefore the value of tangent of ∠M is 42°.

Step-by-step explanation:

Given that,

                  In ΔMNO, ∠O=90°, ON=65, MO=72, and NM=97.

and we have to find the value of tangent of ∠M.

Diagram of the given triangle is shown below:

Now,

ΔMNO is a right angle triangle, so we can use all the trigonometric ratio.

sin\alpha =\frac{Perpendicular}{Hypotenuse}

cos\alpha =\frac{Base}{Hypotenuse}

tan\alpha =\frac{sin\alpha }{cos\alpha } = \frac{Perpendicular}{Base}

tangent of ∠M = \frac{Perpendicular}{Base}

                         = \frac{ON}{MO}

                         = \frac{65}{72}

                         = 0.90278

∴∠M = tan^{-1} (0.90278)

        = 42.0750° ≅ 42°

Therefore the value of tangent of ∠M is 42°.

4 0
2 years ago
Determine the solution set of (3x + 1)2 - 100 = 0.
viktelen [127]
Solve for x.
(3x+1)2-100=0
(3x+1)2=100
3x+1=100/2
3x=50-1
x=49/3
x=16.33333
Hope that helps. If you have any other questions feel free to ask me
5 0
2 years ago
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