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1 year ago

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Most everyday situations involving chance and likelihood are examples of ______. simple probability permutations conditional pro

bability combinations

1 answer:

Fynjy0 [20]1 year ago

6 0

Answer:

Most everyday situations involving chance and likelihood are examples of simple probability.

Explanation:

The probability is the chance or likelihood of any event happening. In our everyday life, we unintentionally use the probability. For example, we say there is 70% chance that tomorrow will be rain, there is 50% chance that Brazil will win the world cup, there is less likelihood of he arriving today and soon. In all these concepts we are dealing with uncertainty and there is chance factor involved in all these examples. So in most everyday situations which involve chance and likelihood are actually examples of simple probability.

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A full bag of dog food weighs 5 1 2 pounds. How much dog food do you have if there are 3 3 4 bags in the cupboard

Ulleksa [173]

You would have 171,008 lbs. of dog food. Because 512 pounds times 334 bags equals 171,008lbs.

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1 year ago

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The angle \theta_1θ

enyata [817]

Answer:

$sin\theta_1 = \dfrac{\sqrt{217}}{19}$

Step-by-step explanation:

It is given that:

$cos\theta_1 = -\dfrac{12}{19}$

And we have to find the value of $sin\theta_1 = ?$

As per trigonometric identities, the relation between $sin\theta\ and \ cos\theta$ can represented as:

$sin^2\theta + cos^2\theta = 1$

Putting $\theta_1$ in place of $\theta$ Because we are given

$sin^2\theta_1 + cos^2\theta_1 = 1$

Putting value of cosine:

$cos\theta_1 = -\dfrac{12}{19}$

$sin^2\theta_1 + (\dfrac{12}{19})^2 = 1\\\Rightarrow sin^2\theta_1 + \dfrac{144}{361} = 1\\\Rightarrow sin^2\theta_1 = 1-\dfrac{144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-144}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{217}{361}\\\Rightarrow sin\theta_1 = +\sqrt{\dfrac{217}{361}}, -\sqrt{\dfrac{217}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{\sqrt{217}}{19}, -\dfrac{\sqrt{217}}{19}$

It is given that $\theta_1$ is in 2nd quadrant and value of sine is always positive in 2nd quadrant. So, the answer is.

$\Rightarrow sin\theta_1 = \dfrac{\sqrt{217}}{19}$

8 0

1 year ago

Match each pair of points to the equation of the line that is parallel to the line passing through the points.

Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point $B(5,2)\ C(7,-5)$

Find the slope BC

Substitute the values in the formula

$m=\frac{-5-2}{7-5}$

$m=\frac{-7}{2}$

$m=-3.5$

so

The equation $y=-3.5x-15$ is parallel to the line passing through the points $B(5,2)\ C(7,-5)$

therefore

<u>the answer Part A) is</u>

$B(5,2)\ C(7,-5)$ ------> $y=-3.5x-15$

<u>Case B)</u> Point $D(11,6)\ E(5,9)$

Find the slope DE

Substitute the values in the formula

$m=\frac{9-6}{5-11}$

$m=\frac{3}{-6}$

$m=-0.5$

so

The equation $y=-0.5x-3$ is parallel to the line passing through the points $D(11,6)\ E(5,9)$

therefore

<u>the answer Part B) is</u>

$D(11,6)\ E(5,9)$ ------> $y=-0.5x-3$

<u>Case C)</u> Point $F(-7,12)\ G(3,-8)$

Find the slope FG

Substitute the values in the formula

$m=\frac{-8-12}{3+7}$

$m=\frac{-20}{10}$

$m=-2$

so

Any linear equation with slope $m=-2$ will be parallel to the line passing through the points $F(-7,12)\ G(3,-8)$

<u>Case D)</u> Point $H(4,4)\ I(8,9)$

Find the slope HI

Substitute the values in the formula

$m=\frac{9-4}{8-4}$

$m=\frac{5}{4}$

$m=1.25$

so

The equation $y=1.25x+4$ is parallel to the line passing through the points $H(4,4)\ I(8,9)$

therefore

<u>the answer Part D) is</u>

$H(4,4)\ I(8,9)$ ------> $y=1.25x+4$

<u>Case E)</u> Point $J(7,2)\ K(-9,8)$

Find the slope JK

Substitute the values in the formula

$m=\frac{8-2}{-9-7}$

$m=\frac{6}{-16}$

$m=-0.375$

so

Any linear equation with slope $m=-0.375$ will be parallel to the line passing through the points $J(7,2)\ K(-9,8)$

<u>Case F)</u> Point $L(5,-7)\ M(4,-12)$

Find the slope LM

Substitute the values in the formula

$m=\frac{-12+7}{4-5}$

$m=\frac{-5}{-1}$

$m=5$

so

The equation $y=5x+19$ is parallel to the line passing through the points $L(5,-7)\ M(4,-12)$

therefore

<u>the answer Part F) is</u>

$L(5,-7)\ M(4,-12)$ ------> $y=5x+19$

8 0

1 year ago

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How do you simplify 77.28/9.2

Alinara [238K]

The answer is 8.4 all you do is divide them together to get your answer.

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2 years ago

The population of Smalltown in the year 1890 was 6,250. Since then, it has increased at a rate of 3.75% each year. • What was th

Vikki [24]

Answer:

year 1915 : 15,689

year 1940 : 39,381

t = 137.9 years

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t

Where:

p = original population

r = growing rate (decimal form)

t= years

A = population after t years

Replacing with the values given:

A = 6,250 (1 + 3.75/100)^t

A = 6,250 (1 + 0.0375)^t

A = 6,250 (1.0375)^t

So, by the year 1915 :

1915-1890 = 25 years passed (t)

A = 6,250 (1.0375)^25

A = 15,689

by the year 1940 :

1940-1890 = 50 years passed (t)

A = 6,250 (1.0375)^50

A = 39,381

When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.

1,000,000= 6,250 (1.0375)^t

1,000,000/ 6,250 =(1.0375)^t

160 = 1.0375^t

log 160 = log 1.0375^t

log 160 = (t ) log 1.0375

log160 / log 1.0375= t

t = 137.9 years

8 0

1 year ago