Solve the following multiplication and division problems.

Mathematics

2 answers:

stealth61 [152]2 years ago

6 0

Answer:

To solve these problems, we just need to multiply or divide.

To solve problem c and d, we need to transform all units to the same, and then operate.

$10yd \times 3yd = 30yd^{2}$

Remember that $yd \times yd = yd ^{2}$

$15ft \times 18 ft = 270 ft^{2}$

$13yd \ 2ft \ 6in \times 15$

To solve this one, we need to transform all lengths to yards. We know that 1 yard equals 3 feet and 1 feet equals 12 inches. So,

$(13yd + 2ft\frac{1yd}{3ft}+6in\frac{1yd}{36in} \times 15\\(13yd+0.67yd+0.17yd) \times 15 =207.6yd$

$(198yd^{2} + 8ft^{2}) \times 7 \\(198yd^{2} + 8ft^{2}\frac{1yd^{2} }{9ft^{2} }) \times 7 \\(198yd^{2} +0.89yd^{2}) \times 7 =1,392.23 yd^{2}$

pshichka [43]2 years ago

4 0

Answer:

Step-by-step explanation:

a. 10 yd.×3 yd.=30 square yards;

b. 15 ft.×18 ft.=279 square feets;

c. 13 yd.=13×3 ft.=39 ft.=39×12 in.=468 in., 2 ft. 6 in.=2×12+6 in.=30 in., then 13 yd. 2 ft. 6 in.×15=498 in. × 15=7470 in.;

d. 198 sq. yd.=198 ×9 sq. ft.=1782 sq. ft.

198 sq. yd. 8 sq. ft. =1782+8 sq. ft.=1790 sq. ft.

Then 1790 sq. ft. × 7=12530 sq. ft.

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Line WY is an altitude in triangle WXZ. If ΔYWZ ~ ΔYXW, what is true about XWZ? XWZ is an obtuse angle. XWZ is a right angle. XW

topjm [15]

<span>In triangle WXZ,

Line WY is an altitude (as shown in the attached picture)
Now, it is given that:
</span><span>If ΔYWZ ~ ΔYXW
</span>∠WXY = ∠WZY
<span>
Then, we can also conclude
</span>∠WYX = ∠WYZ = 90°....(1) (because WY is the altitude)

Now, in any triangle, the sum of all the three angles is 180.

In triangle, WXY, ∠WYX = 90° (From 1)
Therefore, WXY + XWY = 90°

Similarly, in WZY.

Hence, we conclude that XWZ is a right angle.