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skelet666 [1.2K]
2 years ago
6

a local library shows movies on Thursday evening.the library administrator has chosen the next 6 movies he will show , but he ha

s not decided in which order to show them. how many possible orderings of the six movie are there?
Mathematics
2 answers:
Natali [406]2 years ago
7 0
For the first movie he has 6 choices, then for the second since he has chosen the first there are only 5 left, then for the third there are only 4 choices left and so on.

Therefore the answer is 6!=6*5*4*3*2=720 orderings
Llana [10]2 years ago
5 0
So,

We can see that this is a permutation.

The total number of permutations will be the number with an exclamation mark attached to it.

6! = total number of possible permutations
6! = 720

There are 720 possible permutations.
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Answer:

$0.25+$0.05+$0.03=$0.33

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Step-by-step explanation:


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Jamal works as an electrician's apprentice. He rewired 4 electrical outlets in 1 and one-halfhours. If he works at the same pace
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Answer:

We conclude that Jamal will rewired 20 electrical outlets for 7.5 hours.

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We know that Jamal  rewired 4 electrical outlets in 1 and one-half hours. We calculate how many electrical outlets will he rewired for 7.5 hours.

We have the following proportion:

4:1.5=x:7.5\\\\1.5x=4\cdot 7.5\\\\1.5x=30\\\\x=\frac{30}{1.5}\\\\x=20

We conclude that Jamal will rewired 20 electrical outlets for 7.5 hours.

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We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

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R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

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∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).

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