All primes are odd, except two. Therefore the sum of the first million primes is one even number plus 999999 odd numbers. Since odd*odd = odd, the first million primes must be even + odd = odd.
An odd number obviously has an odd final digit, so the only option that can be firmly rules out is b (which is even).
Answer:
t = 0.53 hr
Step-by-step explanation:
We write expressions for the distances walked by these two people, sum them up and set the sum equal to 4 miles:
(3.5 mph)(t) + (4mph)(t) = 4 mi
Combining these terms:
(7.5 mph)(t) = 4 mi
4 mi
Solving for t: t = ---------------- = 0.53 hr
7.5 mph
The total cost of the factory will be the sum of its variable costs and it's fixed costs. The factory has fixed costs of $53,900 and variable costs of $12.50 per unit produced. Let
be the number of toy's produced by this Toby's Tiny Toys, then the total variable costs will be
. From this information we can gather that the cost function for this factory is,

On the other hand, if we let
be the number of toys sold, we can gather that at the selling price of 16.50, the revenue function will be ,

Toby's Tiny Toys will reach their break even point when the total costs are equal to the total revenue. At this break even point ,we have that

The company has to sell 134 750 units to break even.
Answer:
P=2.326
Step-by-step explanation:
Raw Score (X):=1000
Population Mean (μ):=460
Standard Deviation (σ): =Sqrt(npq)
Where n=1000, p=460/1000=0.46 and q=1-0.46=0.54
Sqrt(npq)=sqrt(460X0.54)=15.7607
Z = (X - μ) / σ
Z = (1000 - 460) / 15.7607
Z = 34.26244
For p-value 0.01
P(x=0.01) = 2.32635
Hence, P=2.326 t 3 decimal places.
Answer:
a) see your problem statement for the explanation
b) 2.54539334183
Step-by-step explanation:
(b) Many graphing calculators have a derivative function that lets you define the Newton's Method iterator as a function. That iterator is ...
x' = x - f(x)/f'(x)
where x' is the next "guess" and f'(x) is the derivative of f(x). In the attached, we use g(x) instead of x' for the iterated value.
Here, our f(x) is ...
f(x) = 3x^4 -8x^3 +6
An expression for f'(x) is
f'(x) = 12x^3 -24x^2
but we don't need to know that when we use the calculator's derivative function.
When we start with x=2.545 from the point displayed on the graph, the iteration function g(x) in the attached immediately shows the next decimal digits to be 393. Thus, after 1 iteration starting with 4 significant digits, we have a result good to the desired 6 significant digits: 2.545393. (The interactive nature of this calculator means we can copy additional digits from the iterated value to g(x) until the iterated value changes no more. We have shown that the iterator output is equal to the iterator input, but we get the same output for only 7 significant digits of input.)
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<em>Alternate iterator function</em>
If we were calculating the iterated value by hand, we might want to write the iterator as a rational function in Horner form.
g(x) = x - (3x^4 -8x^3 +6)/(12x^3 -24x^2) = (9x^4 -16x^3 -6)/(12x^3 -24x^2)
g(x) = ((9x -16)x^3 -6)/((12x -24)x^2) . . . . iterator suitable for hand calculation