Question

Given the points below find XY. Round to the nearest hundred. X(-9,2) Y(5,-4)

Answer 1

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-9}~,~\stackrel{y_1}{2})\qquad Y(\stackrel{x_2}{5}~,~\stackrel{y_2}{-4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XY=\sqrt{[5-(-9)]^2+[-4-2]^2}\implies XY=\sqrt{(5+9)^2+(-4-2)^2} \\\\\\ XY=\sqrt{14^2+(-6)^2}\implies XY=\sqrt{232}\implies XY\approx 15.23$

Answer 2

Answer: $XY=15.23$

Step-by-step explanation:

The distance between two points A(a,b) and B (c,d) is given by :-

$AB=\sqrt{(c-a)^2+(d-b)^2}$

The given points : X(-9,2) Y(5,-4)

Then , the distance between two points X(-9,2) Y(5,-4) will be :-

$XY=\sqrt{(5-(-9))^2+(-4-2)^2}\\\\\Rightarrow\ XY\sqrt{(5+9)^2+(-6)^2}\\\\\Rightarrow\ XY=\sqrt{(14)^2+(-6)^2}\\\\\Rightarrow\ XY=\sqrt{196+36}\\\\\Rightarrow\ XY=\sqrt{232}=15.2315462117\approx15.23$

Hence, $XY=15.23$