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Varvara68 [4.7K]
2 years ago
3

Let f(x)=ln(3x) 2.5 . What is the average rate of change of f(x) from 2 to 7? Round your answer to the nearest hundredth. −3.99

−0.25 0.25 3.99
Mathematics
2 answers:
Minchanka [31]2 years ago
7 0

Answer:

Rate of change is 0.25

Step-by-step explanation:

The given function is f(x)=\ln(3x)

The rate of change of function f(x) from a to b is given by

f'(x)=\frac{f(b)-f(x)}{b-a}

We have,

a = 2, b = 7

Thus, rate of change from 2 to 7 is given by

\text{Rate of change}=\frac{f(7)-f(2)}{7-2}\\\\=\frac{\ln(21)-\ln(6)}{7-2}\\\\=\frac{1.25}{5}\\\\=0.25

Thus, rate of change is 0.25

attashe74 [19]2 years ago
3 0

Answer:

Choice C is correct answer.

Step-by-step explanation:

We have given a function.

We have to find average rate of change of function from a to b.

Let f(x) = ln (3x) , a = 2  and b = 7

f(2) = ln(6) and f(7) = ln(21)

Derivative is defined as rate of change of function.

d/dx(f(x)) = f(b)-f(a) / (b-a)

Putting the values of a and b in above formula,we get

d/dx(f(x)) = f(7)-f(2) / 7-2

d/dx(f(x)) = ln(21)-ln(6) / 5

d/dx(f(x)) = 1.25 / 5

d/dx(f(x)) = .25

Average rate of change of function from 2 to 7 is .25


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