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vladimir1956 [14]
2 years ago
5

The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the

paired height/pulse data, the linear correlation coefficient is found to be 0.202. Assuming a 0.01 level of significance, find the critical value. Is there sufficient evidence to support the claim that there is a linear correlation between the heights and pulse rates of women?
Mathematics
1 answer:
Viktor [21]2 years ago
7 0

Answer:

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

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Answer:

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Step-by-step explanation:

we know that

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Step-by-step explanation:

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Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

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\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

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Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

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The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

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