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Rudik [331]
2 years ago
8

An octopus weighted 5/6 kilogram. After two weeks, it's weight has increased by 3/10 kilogram. But afterwards, it lost 1/5 kilog

ram in weight as it was sick. What is it's current weight?
Mathematics
1 answer:
Alex777 [14]2 years ago
5 0

Answer

14/15 kg

Step-by-step explanation:

Rewriting our equation with parts separated

=1+215−15

Solving the fraction parts

2/15−15=?

Find the LCD of 2/15 and 1/5 and rewrite to solve with the equivalent fractions.

LCD = 15

2/15−3/15=−1/15

Combining the whole and fraction parts

1−1/15=14/15

Solution by Formulas

converting mixed numbers to fractions, our initial equation becomes,

17/15−15

Applying the fractions formula for subtraction,

=(17×5)−(1×15)15×5

=85−15/75

=70/75

Simplifying 70/75, the answer is

=14/15

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A box of buttons contains the same number of each type of button. It contains 220g of buttons
ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

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